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maximR
post Jan 1 2014, 04:06 PM

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Critical_Fallacy and v1n0d

Look at what I found !

http://eprints.usm.my/view/subjects/
Flame Haze
post Jan 1 2014, 04:42 PM

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QUOTE(delsoo @ Jan 1 2014, 10:49 AM)
Can anyone guide me to the ans I square? Btw this is my question and working. Cam you figure out which part is wrong
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H is not the height of the triangle, it should be the slant height of the triangle.

user posted image

This post has been edited by Flame Haze: Jan 1 2014, 04:55 PM
TSCritical_Fallacy
post Jan 1 2014, 05:56 PM

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QUOTE(delsoo @ Jan 1 2014, 12:01 PM)
u mean the total surface area only consists of 4 side of the pyramid? but not the base area? sweat.gif
You should thank Flame Haze for showing the detailed workings. Your problem-solving approach is practically right. The triangle Δ area formula is ½×(base of Δ)×(height of Δ), where height of Δ is the slant height of the pyramid. icon_idea.gif

user posted image

First, we settle the total surface area of the pyramid:

user posted image

Applying Pythagoras' theorem to the right triangle of the pyramid, it is VERY OBVIOUS that h² + (b/2)² = s²:

user posted image

Then, we settle the Volume of the pyramid V = (1/3)(b²h):

user posted image

Differentiate

user posted image

To find the maximum volume, set dV/db = 0, and solve for b:

user posted image

Here is the plot of the volume function, V(x):

user posted image
studyboy
post Jan 1 2014, 06:02 PM

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QUOTE(maximR @ Jan 1 2014, 04:06 PM)
Critical_Fallacy and v1n0d

Look at what I found !

http://eprints.usm.my/view/subjects/
*
tongue.gif Why are you so excited? Have a look at the link below:

http://eprints.maths.ox.ac.uk/view/subjects/

See if the above appeals to you. They are mostly applied maths thesis though, not physics unfortunately.
maximR
post Jan 1 2014, 06:07 PM

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QUOTE(studyboy @ Jan 1 2014, 06:02 PM)
tongue.gif Why are you so excited? Have a look at the link below:

http://eprints.maths.ox.ac.uk/view/subjects/

See if the above appeals to you. They are mostly applied maths thesis though, not physics unfortunately.
*
They say I'm weird but delicious things like this make me go " shocking.gif " . I actually prefer this ( although I understand 0.1% of it ) to parties and countdowns .

I still haven't found a friend who has the same wavelength as me . sad.gif

Hopefully at uni , I'll finally be able to talk to someone whose eyes glimmer when reading about stuff like the curving of space-time , even in layman's terms . Nobody is interested in what I'm interested in . Everyone's so career oriented that I want to get out of this shell , this small fishing village to somewhere which hopefully would provide me with academic stimulation which I'd really appreciate .

I've been living for 18 years ( almost ) as a lonely kid , thank Goodness there's this thing called the internet . notworthy.gif

This post has been edited by maximR: Jan 1 2014, 06:08 PM
Flame Haze
post Jan 1 2014, 06:13 PM

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QUOTE(Critical_Fallacy @ Jan 1 2014, 05:56 PM)
You should thank Flame Haze for showing the detailed workings. Your problem-solving approach is practically right. The triangle Δ area formula is ½×(base of Δ)×(height of Δ), where height of Δ is the slant height of the pyramid. icon_idea.gif

user posted image

First, we settle the total surface area of the pyramid:

user posted image

Applying Pythagoras' theorem to the right triangle of the pyramid, it is VERY OBVIOUS that h² + (b/2)² = s²:

user posted image

Then, we settle the Volume of the pyramid V = (1/3)(b²h):

user posted image

Differentiate

user posted image

To find the maximum volume, set dV/db = 0, and solve for b:

user posted image

Here is the plot of the volume function, V(x):

user posted image
*
Nothing wrong if we differentiate V^2 with respect to b right? Less hassle that way biggrin.gif
TSCritical_Fallacy
post Jan 1 2014, 06:27 PM

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QUOTE(Flame Haze @ Jan 1 2014, 06:13 PM)
Nothing wrong if we differentiate V^2 with respect to b right? Less hassle that way  biggrin.gif
You mean Implicit Differentiation? Of course! wink.gif

user posted image
Flame Haze
post Jan 1 2014, 06:31 PM

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QUOTE(Critical_Fallacy @ Jan 1 2014, 06:27 PM)
You mean Implicit Differentiation? Of course! wink.gif

user posted image
*
Hey I never though of this. Before this I used to just find the value of b when V^2 is maximum, sub. it back into the equation for V, based on the assumption when V is maximum, V^2 is maximim too. But I think it has a few flaws. What if V had a maximum value of 3 and a minimum value of -7, then the maximum value of V^2 is 49, right? Which means the b got from the maximum value of V^2 isn't the b for the maximum value of V. sweat.gif

P.S Can you show me the same graph for range -10<x<10?

This post has been edited by Flame Haze: Jan 1 2014, 06:34 PM
TSCritical_Fallacy
post Jan 1 2014, 07:17 PM

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QUOTE(Flame Haze @ Jan 1 2014, 06:31 PM)
Hey I never though of this. Before this I used to just find the value of b when V^2 is maximum, sub. it back into the equation for V, based on the assumption when V is maximum, V^2 is maximim too. But I think it has a few flaws. What if V had a maximum value of 3 and a minimum value of -7, then the maximum value of V^2 is 49, right? Which means the b got from the maximum value of V^2 isn't the b for the maximum value of V.  sweat.gif

P.S Can you show me the same graph for range -10<x<10?
Depends on the behavior of function V(x), the graph must not have a global maxima and a local maxima at the same time. Since the graph (Quartic function) is symmetrical, having 2 repeated roots at the origin, and 2 distinct roots (equal magnitude but different sign), therefore, your bold approach is perfectly feasible in this case. From the graph y = V², you can see

user posted image

Compare it to original function V(x). Beyond x > 6 and x < -6, the function requires complex number treatment.

user posted image

Your approach does not work in the following graph because it has a global maxima and a local maxima.

user posted image

This post has been edited by Critical_Fallacy: Jan 1 2014, 07:18 PM
danny88888
post Jan 1 2014, 08:02 PM

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Let A be an (n x n) matrix satisfying 2I - A = A^5. Find an expression for the inverse of A.

2(AA*-1) = A*5+A
A*-1 = (A*5+A/2A)
A*-1= 1/2A*4 + 1/2

This is my answer, but the answer sheet says
A*-1 = 1/2A*4 +1/2I ( why is there an I?) anyone can explain it to me ? @Critical_Fallacy

delsoo
post Jan 1 2014, 08:19 PM

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QUOTE(Flame Haze @ Jan 1 2014, 04:42 PM)
H is not the height of the triangle, it should be the slant height of the triangle.

user posted image
*
Thanks for your effort!
studyboy
post Jan 1 2014, 08:26 PM

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QUOTE(danny88888 @ Jan 1 2014, 08:02 PM)
Let A be an (n x n) matrix satisfying 2I - A = A^5. Find an expression for the inverse of A.

2(AA*-1) = A*5+A
A*-1 = (A*5+A/2A)
A*-1= 1/2A*4 + 1/2

This is my answer, but the answer sheet says
A*-1 = 1/2A*4 +1/2I ( why is there an I?) anyone can explain it to me ? @Critical_Fallacy
*
Hmm, something is very wrong with this. You are working with a matrix. How is it possible for 1 to appear in the equation?
delsoo
post Jan 1 2014, 08:36 PM

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QUOTE(Critical_Fallacy @ Jan 1 2014, 05:56 PM)
You should thank Flame Haze for showing the detailed workings. Your problem-solving approach is practically right. The triangle Δ area formula is ½×(base of Δ)×(height of Δ), where height of Δ is the slant height of the pyramid. icon_idea.gif

user posted image

First, we settle the total surface area of the pyramid:

user posted image

Applying Pythagoras' theorem to the right triangle of the pyramid, it is VERY OBVIOUS that h² + (b/2)² = s²:

user posted image

Then, we settle the Volume of the pyramid V = (1/3)(b²h):

user posted image

Differentiate

user posted image

To find the maximum volume, set dV/db = 0, and solve for b:

user posted image

Here is the plot of the volume function, V(x):

user posted image
*

thanks for your different way of approach!

studyboy
post Jan 1 2014, 08:45 PM

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QUOTE(maximR @ Jan 1 2014, 06:07 PM)
They say I'm weird but delicious things like this make me go "  shocking.gif  " . I actually prefer this ( although I understand 0.1% of it ) to parties and countdowns .

I still haven't found a friend who has the same wavelength as me .  sad.gif

Hopefully at uni , I'll finally be able to talk to someone whose eyes glimmer when reading about stuff like the curving of space-time , even in layman's terms . Nobody is interested in what I'm interested in . Everyone's so career oriented that I want to get out of this shell , this small fishing village to somewhere which hopefully would provide me with academic stimulation which I'd really appreciate .

I've been living for 18 years ( almost ) as a lonely kid , thank Goodness there's this thing called the internet .  notworthy.gif
*
Oh you will find people who share your interests so fret not! University is full of people studying purely for seeking knowledge. You needn't worry about being lonely anymore! laugh.gif


Flame Haze
post Jan 1 2014, 08:47 PM

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QUOTE(studyboy @ Jan 1 2014, 08:45 PM)
Oh you will find people who share your interests so fret not! University is full of people studying purely for seeking knowledge. You needn't worry about being lonely anymore!  laugh.gif
*
sorry i seek money and waifu only sad.gif
studyboy
post Jan 1 2014, 09:15 PM

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QUOTE(Flame Haze @ Jan 1 2014, 08:47 PM)
sorry i seek money and waifu only  sad.gif
*
Lol! Then you are on the right path too! tongue.gif What do you want to study and where if you do not mind me asking?
Flame Haze
post Jan 1 2014, 09:42 PM

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QUOTE(studyboy @ Jan 1 2014, 09:15 PM)
Lol! Then you are on the right path too!  tongue.gif What do you want to study and where if you do not mind me asking?
*
Accounting & Finance, at LSE sweat.gif
studyboy
post Jan 1 2014, 09:57 PM

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QUOTE(Flame Haze @ Jan 1 2014, 09:42 PM)
Accounting & Finance, at LSE  sweat.gif
*
Good stuff! LSE is the place to be for that but competition for jobs or internships is so stiff there! My fellow LSE mate once told me that at LSE the primary goal for a student is to look for a job! The next priority will be studies! biggrin.gif

Ah! Why don't you try Business Maths and Stats? You are good in the subject!
Flame Haze
post Jan 1 2014, 10:33 PM

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QUOTE(studyboy @ Jan 1 2014, 09:57 PM)
Good stuff! LSE is the place to be for that but competition for jobs or internships is so stiff there! My fellow LSE mate once told me that at LSE the primary goal for a student is to look for a job! The next priority will be studies!  biggrin.gif

Ah! Why don't you try Business Maths and Stats? You are good in the subject!
*
Parents are both accountants. Pathway laid out edi. sweat.gif
maximR
post Jan 1 2014, 10:37 PM

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QUOTE(Flame Haze @ Jan 1 2014, 10:33 PM)
Parents are both accountants. Pathway laid out edi.  sweat.gif
*
Oh . But it'd be better if you do what you love . smile.gif

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