P_gas
=hpg + P_atm
=0.1(1.36x10⁴)(10) + 1.03 x 10⁵
=1.166 x 10⁵ Pa

log₂ 4 + [(log₂ (p-6)²)/(log₂ 4)]= log₂ p
4(1/2)((p-6)²) = p
2p² - 24p - p + 72 = 0
(2p-9)(p-8) = 0
p = 4.5, 8

*edited, pressed calculator wrongly.

This post has been edited by HotChocolate: Nov 1 2008, 07:54 PM

not tis ans wor

I try..

2 + 2log 4 (p-6) = log 2 p

2 log 4 (p-6) - log 2 p = -2
log 4 (p-6)^2 - log 2 p = 2
[log 2 (p-6)^2 / log 2 2^2] - log 2 p = -2
[log 2 (p-6)^2 / 2] - log 2 p = -2
log 2 (p-6)^2 - 2 log 2 p = -2(2)
log 2 (p-6)^2 - log 2 p^2 = -4
log 2 [(p^2 - 12p + 36) / p^2] = -4
(p^2 - 12p + 36) / (p^2)= 2^-4
p^2 - 12p + 36 = (1/16)p^2
(15/16)p^2 - 12p + 36 = 0
p = ...

Fixed for errors

This post has been edited by Leto Kynes: Nov 1 2008, 08:59 PM

i heard english paper going to be hard
vick how many a's u got for trials?

vick is only form 4 student.
LOL! Don't believe it, right?

He really form 4 student..

-- *hehe* - quickly reedit

Good Luck SPM candidates. You only have less than two weeks time for final preparation.


This post has been edited by work_tgr: Nov 1 2008, 08:51 PM

i think u made an error there.. u switched '2' over to the right yet but you did not put a negative sign infront of it..
should have been:

2 log 4 (p-6) - log 2 p = -2
log 4 (p-6)^2 - log 2 p =-2
[log 2 (p-6)^2 / log 2 2^2] - log 2 p = -2
[log 2 (p-6)^2 / 2] - log 2 p = -2
log 2 (p-6)^2 - 2 log 2 p = -2(2)
log 2 (p-6)^2 - log 2 p^2 =- 4
log 2 [(p^2 - 12p + 36) / p^2] = -4
(p^2 - 12p + 36) = 2^-4p^2
p^2 - 12p + 36 = 1/16p^2
15/16p^2 - 12p + 36 = 0
p=4.8 , 8



is this right?

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Added on November 1, 2008, 8:55 pmto be a little bit more precise, it's more like 1 weeks to spm.. damn..

This post has been edited by mych91: Nov 1 2008, 08:55 PM

You're right.. my bad.. made the simplest error Hope your answer is right, at least!

work_tgr I don't think you can just remove the log like that

why not?
simple example:
x=y
log10 (x)= log10 (y)

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Added on November 1, 2008, 9:01 pmuhhuuu!! Every body cell is getting excited!

This post has been edited by work_tgr: Nov 1 2008, 09:01 PM

oh.. ok

mych and I got two values for p though =x

need vick to post the ans

haha.. yeah hopefully..
what work_tgr did wrong was he/she didnt change the equation from log base 4 to log base 2.otherwise, if all are in log with the same base, it is possible that all logs be canceled out.

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Added on November 1, 2008, 9:05 pmneeeddd more add math questionss!!..
anyone?

This post has been edited by mych91: Nov 1 2008, 09:05 PM

LOL! .. base 2 liao leh
--

I know the second step looks "suspicious" to you ... but

This post has been edited by work_tgr: Nov 1 2008, 09:12 PM

oh crap.. thousand apologies..
my bad.. yeah you're right.. you DID change to base 2.. cause it gets kinda confusing when u leave out the changing base step
man.. why are there so many variations to the answer to dis question

Stress vs music = ?

A piece of stone weighing 600 g at 28 degree celcius is put into a beaker which contain 1.2 kg of water at 50 degree celcius. calculate the final temperature of the water and the stone.
(Specific heat capacity=4200, specific heat capacity of stone=840)

0.6(840)(T-28) = 1.2(4200)(50-T)
504(T-28) = 5040(50-T)
504T - 14112 = 252000 - 5040T
5544T = 266112
T = 48

Correct me if I'm wrong

ur ans is correct but how did u get 1.2x4200x(50-T)
why not T-50 ?
bcoz it asked for the stone final temperature. im confused

because the final temperature must lower than 50 and higher than 28