RED-HAIR-SHANKS Bean17 sagethesausage Have you finished the Maths (T) coursework?

For my class , we haven't even started yet
Neither did the teacher mention a word of it

Huh? I thought it's the same for every school?

help me!!!

Is the substitution is t= tan (x/2)
And the answer is 1/4 tan (x/2) + 1/12 tan ^3 (x/2) + c ?

i'm not sure..
how u do it? can u show me..

Hei guys, before you guys sit for the exam I think it's useful to read the reports on STPM 2013 here. Common mistakes make by candidates are highlighted and reading them might help you to prevent making mistakes you do not know are mistakes now.

You can also see some papers in first term almost have a 50% failure, so please don't play play and take it serious.

This post has been edited by Just Visiting By: Mar 29 2015, 12:03 AM

Guys,
Here's the latest timetable for second term STPM:


The date has been carried forward to 14th May of 2015. Please take note about that.

This post has been edited by scgoh123: Apr 5 2015, 08:06 PM

How is everyone's Chemi Project going on? What topic are you working on?

can someone show me how to do coursework math(T) question 2(b).. pleaseeeeeeeeeeeeee

Critical_Fallacy RED-HAIR-SHANKS Can you show some light on how to deal with part (b)? Since most of us are having problem here.

Here's the question:

Is that supposed to be a demand or a question?

In part 1b, you have V(x,y), then substituting x(y) gives V(y).
Part 2b is something about dV/dt, so something something derivative something something.

-deleted-

This post has been edited by tree_0802: Apr 11 2015, 06:30 PM

Is that supposed to be a demand or a question?

a question..


Attached thumbnail(s)

Please ask properly, thank you.

This problem is related to the Nuclear Cooling Tower or Hyperboloid Structure.

If you are referring to 1(b), you can simplify the problem by shifting the y-axis.

Using the Disk Method, you should obtain something like this:



where h is the height of the water level.

Clue #1: Find a way to make this substitution:

Clue #2: Use Trigonometric Identities (after solving Clue #1).

For 2(b), using the Chain Rule, , find

(i).

(ii).

Since is given and can be obtained from the derivative of 1(b), the rest is Algebra and you can find the extrema on the closed interval .

For completeness, you should also determine the height of the water level at which the minimum and maximum of dh/dt occur.

scgoh123

For 2(b), I've got this. The max (1.22 m/hr) occurs around the bottleneck (8.36 m) of the Hyperboloid Container. Does it make sense to you?



When you get , it all goes back to the quadratics.



For your info, the dh/dt does not have a minimum in the calculus sense, but it contains an Infimum, which is the greatest lower bound on h ∈ [0, 14]. You can imagine that, as the water level is approaching 14 m, the flow rate dV/dt ≈ 0, causing the water level to increase extremely slow (to prevent overflow), and therefore dh/dt ≈ 0. It is inaccurate to put exactly dh/dt = 0, because that means the flow control valve is turned off completely (dV/dt = 0). Since dV/dh is non-zero, the Chain Rule becomes indeterminate. The argument of 2(b) is built on the assumption that the water is being pumped continuously into the cooling tower until it stops at the water level 14 m. Naturally, when you stop pumping water, the water level stops increasing.

Please note that in this case, the maximum is also the Supremum (the least upper bound) of the set.

This post has been edited by Critical_Fallacy: Apr 13 2015, 05:20 PM

The problem that i had faced is when I tried to substitute h=14 into the differential equation that I have obtained, the time taken is infinity. The container will never be filled. So how do I calculate the time taken to fill up the container?