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 Ask a Mathematical Physicist

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VengenZ
post Nov 17 2013, 06:31 PM

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QUOTE(ailing tan @ Nov 17 2013, 03:39 PM)
why this is B why not A???
*
Adiabatic compression curve should be steeper than isothermal's. Since the gas is adiabatically compressed, so the temperature must've increased, therefore the adiabatic curve must be located above the isothermal curve.
ailing tan
post Nov 17 2013, 06:55 PM

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ok ... thanks .... can you show how to get the ans for this question ??? help!!


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TSCritical_Fallacy
post Nov 18 2013, 02:23 AM

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QUOTE(ailing tan @ Nov 17 2013, 05:31 PM)
if i am given a question like this [ the parametric equations of curve is x = t*(t+2) y = 2*(t+1) ] How to know that this curve is ellipse, parabola, or hyperbola at first glance??
Like crazywing26 said, you hardly know which conic section is unless you have done many practices. However, it's not the end of maths. With a little quick-witted algebraic manipulation skills plus some knowledge in trigonometric identities, you can derive the General Parametric Equations for parabola, ellipse, and hyperbola. The parametric equations of a circle with radius r can be derived from the parametric equations of an ellipse by setting a = b = r.

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TSCritical_Fallacy
post Nov 18 2013, 03:41 AM

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QUOTE(Flame Haze @ Nov 17 2013, 03:52 PM)
This is complicated  biggrin.gif

Let s = 1+2+4+8+....
So 2s = 2+4+8+16....
And s-1 = 2+4+8+16+...

Seems to stand true that 2s = s-1
How come s = -1?  sweat.gif
QUOTE(reconnaissance @ Nov 18 2013, 02:24 AM)
However, can it be explained this way?;

2s = s-1
2s-s = (s-1)-s
s = -1
There might be a more sinister motive behind the smiley. Well, straight to the point, it's a mathematical fallacy, where it presents an invalid proof for 3 reasons as explained in the following:

Reason #1: s has no sum.
s = 1 + 2 + 4 + 8 + … + 2^n is the infinite series whose terms are the successive powers of two. It is logically obvious that the sum of ever-growing positive-definite terms does not converge at a negative value or s = −1. In other words, it diverges to infinity, and so in the usual sense it has no sum.

Reason #2: Division-by-zero fallacy.
Let's start from here: 2s = s − 1. We know s is said to tend to infinity (∞). Using the notion of infinite limits, we can generalize that s − 1 becomes extremely close to s as s approaches indefinitely to infinity (∞).

And so, it follows that
2s = s
Divide by the non-zero s
2 = 1
The fallacious result is the implicit assumption that dividing by 0 is a legitimate operation
2 × 0 = 1 × 0
Dividing by zero gives:
2 × (0/0) = 1 × (0/0)

Reason #3: Invalid argument of power series.
Using Maclaurin series expansion, one can show that 1/(1 − x) = 1 + x + x² + x³ + …
If we plug in x = 2, the series becomes s and it sums the terms on the RHS to the finite value of −1.
Unfortunately, the expansion is only VALID for arguments |x| < 1. In plain English, invalid argument yields invalid result.

This post has been edited by Critical_Fallacy: Nov 18 2013, 03:43 AM
ailing tan
post Nov 18 2013, 03:05 PM

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i gt a physics question here...
A surface area A is bombarded normally by n molecules per unit second.. If the collision are elastic each molecule has a mass of m and moves with speed u , hence the pressure actiong on surface is 2nmu... how to get the ans??? icon_question.gif icon_question.gif
TSCritical_Fallacy
post Nov 18 2013, 06:27 PM

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QUOTE(ailing tan @ Nov 18 2013, 03:05 PM)
i gt a physics question here...
A surface area A is bombarded normally by n molecules per unit second.. If the collision are elastic each molecule has a mass of m and moves with speed u , hence the pressure actiong on surface is 2nmu...  how to get the ans???  icon_question.gif  icon_question.gif
The information given on your physics question are incomplete. No assumptions are made. However, this is my probable explanation of the elastic collision. Do you get the concept? sweat.gif

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ailing tan
post Nov 18 2013, 06:31 PM

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sry i cant understand this....haha.. this is too difficult for me...
TSCritical_Fallacy
post Nov 18 2013, 06:44 PM

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QUOTE(ailing tan @ Nov 18 2013, 06:31 PM)
sry i cant understand this....haha.. this is too difficult for me...
Perhaps you can ask your classmates, Just Visiting By or crazywing26 to explain to you. By the way, are you familiar with the fundamentals of Linear Momentum and Elastic Collision in One Dimension? icon_question.gif

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crazywing26
post Nov 18 2013, 08:38 PM

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QUOTE(ailing tan @ Nov 18 2013, 03:05 PM)
i gt a physics question here...
A surface area A is bombarded normally by n molecules per unit second.. If the collision are elastic each molecule has a mass of m and moves with speed u , hence the pressure actiong on surface is 2nmu...   how to get the ans???  icon_question.gif  icon_question.gif
*
The question given has incomplete information. To sum up, @Critical_Fallacy made an assumption (not exactly that way but I think it can be assumed as this way) of the molecules bounce on a wall (remains at rest after the collision, the particles won't push the wall to move right? flex.gif). So I suppose that is the crucial information you have missed out.

This post has been edited by crazywing26: Nov 18 2013, 10:11 PM
TSCritical_Fallacy
post Nov 21 2013, 03:01 PM

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2013 STPM Maths T paper: Part 1 & Part 2

Hi ailing tan, crazywing26, iChronicles, yellowpika, ystiang

Here is my solution for Question 1 ~ [8 marks]:

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TSCritical_Fallacy
post Nov 21 2013, 03:02 PM

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2013 STPM Maths T paper: Part 1 & Part 2

Hi ailing tan, crazywing26, iChronicles, yellowpika, ystiang

Here is my solution for Question 2 ~ [7 marks]:

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TSCritical_Fallacy
post Nov 21 2013, 03:02 PM

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2013 STPM Maths T paper: Part 1 & Part 2

Hi ailing tan, crazywing26, iChronicles, yellowpika, ystiang

Here is my solution for Question 3 ~ [5 marks]:

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TSCritical_Fallacy
post Nov 21 2013, 03:03 PM

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2013 STPM Maths T paper: Part 1 & Part 2

Hi ailing tan, crazywing26, iChronicles, yellowpika, ystiang

Here is my solution for Question 4 ~ [9 marks]:

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ailing tan
post Nov 21 2013, 03:31 PM

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can you show the ans for no6??
TSCritical_Fallacy
post Nov 21 2013, 06:36 PM

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2013 STPM Maths T paper: Part 1 & Part 2

Hi ailing tan, crazywing26, iChronicles, WoanPing, yellowpika

Here is my solution for Question 5 ~ [9 marks]:

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TSCritical_Fallacy
post Nov 21 2013, 06:37 PM

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2013 STPM Maths T paper: Part 1 & Part 2

Hi ailing tan, crazywing26, iChronicles, WoanPing, yellowpika

Here is my solution for Question 6 ~ [7 marks]:

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crazywing26
post Nov 21 2013, 06:37 PM

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QUOTE(Critical_Fallacy @ Nov 21 2013, 03:01 PM)
2013 STPM Maths T paper: Part 1 & Part 2

Hi ailing tan, crazywing26, iChronicles, yellowpika, ystiang

Here is my solution for Question 1 ~ [8 marks]:

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*
Although your solutions for the inequality is true, but the question stated "Hence". So I think we need to solve this question by finding the intersection point. And then refer to the graph, straight away write the answer for range of x (-<infinity> 1-<surd>3] or [0, <infinity>) and the answer is supposed to be in set notation.

And very thank you for providing us solutions with working. XD

This post has been edited by crazywing26: Nov 21 2013, 06:42 PM
TSCritical_Fallacy
post Nov 21 2013, 06:37 PM

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2013 STPM Maths T paper: Part 1 & Part 2

Hi ailing tan, crazywing26, iChronicles, WoanPing, yellowpika

Repost of solution for Question 7 ~ [15 marks]:

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TSCritical_Fallacy
post Nov 21 2013, 06:38 PM

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2013 STPM Maths T paper: Part 1 & Part 2

Hi ailing tan, crazywing26, iChronicles, WoanPing, yellowpika

Repost of solution for Question 8 ~ [15 marks]:

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TSCritical_Fallacy
post Nov 22 2013, 11:41 PM

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Hi maximR, this is Remainder Theorem. Most likely you will master this in less than 3 minutes. laugh.gif

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