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 -SPM Thread Version Four-, Its never too late! :)

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1malaysia
post Nov 28 2010, 10:20 PM

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QUOTE(jasss @ Nov 28 2010, 10:11 PM)
@Naz
1. Given 8^(x-3) = 4^2x / 64 , find value of x
2^3(x-3)=2^4x / 2^6
2^(3x-9)=2^(4x-6)
3x-9=4x-6
x=-3

2. If it's given PA = 2PB .. The ratio is 2 for PA while 1 for PB ? or??
PA/PB=2/1
PA:PB=2:1

3. The vectors a~ and b~ are non-zero and parallel. It is given that (8h-1) a~ = (2k+8)b~ , where h and k are constant. Find the value of h and of k
8h-1=0
h=1/8
2k+8=0
k=-4

4. It is given that sin teta = p , where p is a constant and 90 < teta < 180
Find in terms of p
sin teta=p, cos teta=-square root(1-p^2), tan teta=-p/square root(1-p^2)
a) sec teta=1/cos teta= -1/square root(1-p^2)
b) cos 2teta=1-2sin^2 teta =1-2p^2

5. Given y = ( x - 3 )^2 ( 2x - 5 ), find d^2y/dx^2
y=(x-3)^2 (2x - 5)
_=(x^2 -6x +9)(2x-5)
_=2x^3 - 5x^2 - 12x^2 +30x +18x - 45
_=2x^3 - 17x^2 + 48x - 45 

dy/dx=6x^2 - 34x + 48
d^2y/dx^2=12x -34

6. Two variables , x and y are related by the eq y = 2x^2 - 3 / x, find
dy/dx when x = 3 .
y=2x^2 - 3/x
dy/dx=4x+3/x^2
_____=4(3)+3/9
_____=37/3

7. Given six letter cards

F R I E N D
--> Fours card are arranged to form four-lettered words.
Find, The probability that the words formed have all the consonants.
4P4=24

Well, that my answer, please tell me am i correct for these question. tongue.gif
*
i tot number 7 is asking probability. not the number of ways.

i think shld b 4P4/6P4
jasss
post Nov 28 2010, 10:21 PM

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QUOTE(1malaysia @ Nov 28 2010, 02:20 AM)
i tot number 7 is asking probability. not the number of ways.

i think shld b 4P4/6P4
*
Thank 4 correct me.
Zaazuu
post Nov 28 2010, 10:23 PM

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Eh, guys, for Math you need compass ar ?
ariff02
post Nov 28 2010, 10:23 PM

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QUOTE(limhongwoon @ Nov 28 2010, 10:19 PM)
If ogive , we need to have cumulative frequency and how about histogram ? Lower boundary and upper boundary ? If frequency ? Midpoint
*
Ogive = culmulative freaquency

Histogram = lower and upper boundries

Frequency Polygon = Midpoint, but remember start from 0 frequency!


Added on November 28, 2010, 10:23 pm
QUOTE(ariff02 @ Nov 28 2010, 10:23 PM)
Ogive = culmulative freaquency

Histogram = lower and upper boundries

Frequency Polygon = Midpoint, but remember start from 0 frequency! and end with 0 too
*
This post has been edited by ariff02: Nov 28 2010, 10:23 PM
syaza_pitt
post Nov 28 2010, 10:27 PM

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any tips for AGAMA??
really need helps here.
waie
post Nov 28 2010, 10:33 PM

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From: Boh tanyak kamek


QUOTE(syaza_pitt @ Nov 28 2010, 10:27 PM)
any tips for AGAMA??
really need helps here.
*
» Click to show Spoiler - click again to hide... «


I dono how true is that, but guess better try at least
iAdor3 Naz
post Nov 28 2010, 10:47 PM

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QUOTE(jasss @ Nov 28 2010, 10:11 PM)
@Naz
1. Given 8^(x-3) = 4^2x / 64 , find value of x
2^3(x-3)=2^4x / 2^6
2^(3x-9)=2^(4x-6)
3x-9=4x-6
x=-3

2. If it's given PA = 2PB .. The ratio is 2 for PA while 1 for PB ? or??
PA/PB=2/1
PA:PB=2:1

3. The vectors a~ and b~ are non-zero and parallel. It is given that (8h-1) a~ = (2k+8)b~ , where h and k are constant. Find the value of h and of k
8h-1=0
h=1/8
2k+8=0
k=-4

4. It is given that sin teta = p , where p is a constant and 90 < teta < 180
Find in terms of p
sin teta=p, cos teta=-square root(1-p^2), tan teta=-p/square root(1-p^2)
a) sec teta=1/cos teta= -1/square root(1-p^2)
b) cos 2teta=1-2sin^2 teta =1-2p^2

5. Given y = ( x - 3 )^2 ( 2x - 5 ), find d^2y/dx^2
y=(x-3)^2 (2x - 5)
_=(x^2 -6x +9)(2x-5)
_=2x^3 - 5x^2 - 12x^2 +30x +18x - 45
_=2x^3 - 17x^2 + 48x - 45 

dy/dx=6x^2 - 34x + 48
d^2y/dx^2=12x -34

6. Two variables , x and y are related by the eq y = 2x^2 - 3 / x, find
dy/dx when x = 3 .
y=2x^2 - 3/x
dy/dx=4x+3/x^2
_____=4(3)+3/9
_____=37/3

7. Given six letter cards

F R I E N D
--> Fours card are arranged to form four-lettered words.
Find, The probability that the words formed have all the consonants.
4P4=24

Well, that my answer, please tell me am i correct for these question. tongue.gif
*
4. It is given that sin teta = p , where p is a constant and 90 < teta < 180
Find in terms of p
sin teta=p, cos teta=-square root(1-p^2), tan teta=-p/square root(1-p^2)
a) sec teta=1/cos teta= -1/square root(1-p^2)
b) cos 2teta=1-2sin^2 teta =1-2p^2

CAN YOU EXPLAIN THAT TO ME? Can't understand

2. If it's given PA = 2PB .. The ratio is 2 for PA while 1 for PB ? or??
PA/PB=2/1
PA:PB=2:1

Are u sure this is right? So PA is 2 , while PB is 1 right? Hmm.. I do it like that also.. but the scheme give the other way round -.-"

6. Two variables , x and y are related by the eq y = 2x^2 - 3 / x, find
dy/dx when x = 3 .
y=2x^2 - 3/x
dy/dx=4x+3/x^2
_____=4(3)+3/9
_____=37/3

I'm sorry but the answer is 7/3

AND ALSO.. FOR NON-ZERO and Parallel is equal to zero?.. while for the other way round, we have to add K right? hmm


Added on November 28, 2010, 10:48 pm
QUOTE(waie @ Nov 28 2010, 10:33 PM)
» Click to show Spoiler - click again to hide... «


I dono how true is that, but guess better try at least
*
I'll read all, but will read the tips for TAMADUN and TOKOH.. thanks =]

This post has been edited by iAdor3 Naz: Nov 28 2010, 10:48 PM
jasss
post Nov 28 2010, 11:01 PM

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[quote=iAdor3 Naz,Nov 28 2010, 02:47 AM]
2. If it's given PA = 2PB .. The ratio is 2 for PA while 1 for PB ? or??
PA/PB=2/1
PA:PB=2:1

Are u sure this is right? So PA is 2 , while PB is 1 right? Hmm.. I do it like that also.. but the scheme give the other way round -.-"
I almost do this kind of question like this but dunno why d answer will different.


6. Two variables , x and y are related by the eq y = 2x^2 - 3 / x, find
dy/dx when x = 3 .
y=2x^2 - 3/x
dy/dx=4x+3/x^2
_____=4(3)+3/9
_____=37/3

I'm sorry but the answer is 7/3
HUH? How come?

AND ALSO.. FOR NON-ZERO and Parallel is equal to zero?.. while for the other way round, we have to add K right? hmm
normally yes. (8h-1) a~ = (2k+8)b~ there dont h any a~ at d other side. so, even we add K, it still d same.

Question 2 n 6 from which state/
iAdor3 Naz
post Nov 28 2010, 11:02 PM

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All from N9 ..
Thanks ya.. I screwed in paper 1 -.-".. Paper 2 is food LOL ~

This post has been edited by iAdor3 Naz: Nov 28 2010, 11:02 PM
henry930821
post Nov 28 2010, 11:12 PM

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Just double checking this question.
Round off 979560 correct to three significant figures. Whats your answer?
556611
post Nov 28 2010, 11:15 PM

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QUOTE(henry930821 @ Nov 28 2010, 11:12 PM)
Just double checking this question.
Round off 979560 correct to three significant figures. Whats your answer?
*
my answer is 980000
hi guys anyone here knows why this question is D?



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jasss
post Nov 28 2010, 11:18 PM

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@naz
2. PA=2PB
(x-2)^2 + (y-0)^2 = 4[(x-0)^2+(y-7)^2]
x^2-4x+4 +y^2=4x^2+4y^2+56y+196
3x^2+3y^2+4x+56y+192=0
Well, i dunno why u nid 2 use ratio?

For question 6, sori, i tot is 2x^2 - 3/x.
y=(2x^2 - 3)/x
_=2x - 3/x
dy/dx=2 + 3/X^2
_____=2+ 3/9
_____= 7/3
LordReaper
post Nov 28 2010, 11:20 PM

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QUOTE(556611 @ Nov 28 2010, 11:15 PM)
my answer is 980000
hi guys anyone here knows why this question is D?
*
velocity is displacement/time
so displacement is squareroot(4^2+5^2) = 6.403km
den use 6.403/2 = 3.2kmh-1

This post has been edited by LordReaper: Nov 28 2010, 11:21 PM
jasss
post Nov 28 2010, 11:23 PM

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QUOTE(556611 @ Nov 28 2010, 03:15 AM)
my answer is 980000
hi guys anyone here knows why this question is D?
*
this question ask for velocity, so we nid to find d displacement not distance.
displacement^2=4^2 + 5^2
displacement=6.4
velocity=6.4/2=3.2
1malaysia
post Nov 28 2010, 11:24 PM

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QUOTE(556611 @ Nov 28 2010, 11:15 PM)
my answer is 980000
hi guys anyone here knows why this question is D?
*
velocity = rate of change of displacement

hope u get it smile.gif
556611
post Nov 28 2010, 11:28 PM

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QUOTE(LordReaper @ Nov 28 2010, 11:20 PM)
velocity is displacement/time
so displacement is squareroot(4^2+5^2) = 6.403km
den use 6.403/2 = 3.2kmh-1
*
yup mind to explain/?


Added on November 28, 2010, 11:30 pm
QUOTE(1malaysia @ Nov 28 2010, 11:24 PM)
velocity = rate of change of displacement

hope u get it smile.gif
*
opps haha thanks for reminding me..i misread the question vmad.gif i thought he ran from south to north XD
thanks once again!

This post has been edited by 556611: Nov 28 2010, 11:30 PM
iAdor3 Naz
post Nov 28 2010, 11:46 PM

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QUOTE(jasss @ Nov 28 2010, 11:18 PM)
@naz
2. PA=2PB
(x-2)^2 + (y-0)^2 = 4[(x-0)^2+(y-7)^2]
x^2-4x+4 +y^2=4x^2+4y^2+56y+196
3x^2+3y^2+4x+56y+192=0
Well, i dunno why u nid 2 use ratio?

For question 6, sori, i tot is 2x^2 - 3/x.
y=(2x^2 - 3)/x
_=2x - 3/x
dy/dx=2 + 3/X^2
_____=2+ 3/9
_____= 7/3
*
Oh.. then no need ratio? OMG
=.=".. just direct put the formula then huh? -.-"..
Btw thanks
Just crossing fingers.. less differentiation and integration questiosn LOL ~
jasss
post Nov 28 2010, 11:47 PM

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QUOTE(iAdor3 Naz @ Nov 28 2010, 03:46 AM)
Oh.. then no need ratio? OMG
=.=".. just direct put the formula then huh? -.-"..
Btw thanks
Just crossing fingers.. less differentiation and integration questiosn LOL ~
*
normally i use ratio to find d point that involve midpoint.
iAdor3 Naz
post Nov 28 2010, 11:49 PM

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QUOTE(jasss @ Nov 28 2010, 11:47 PM)
normally i use ratio to find d point that involve midpoint.
*
I'm not very bad in add maths.. but the ratio really makes me confuse

like PA = 2PB , PA : PB = 3 : 2 .. PQ : QV = 1 : 3

OMG LOL xD
556611
post Nov 29 2010, 12:05 AM

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hmm in this question..what formulae we should use?
E=1/2Fx? by using this formulae i'll get the answer D but answer given is C actually/...
and could it be E=F x s? but why not 1/2Fx?


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