-SPM Thread Version Four-, Its never too late! :)
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 Nov 26 2010, 11:40 PM
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Senior Member
1,372 posts Joined: Sep 2008  
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QUOTE(fisherman10 @ Nov 27 2010, 12:34 AM) guys!! it wont happen la damit. every year also bocor. resit, bocor again la. why botheranyone of u got heard the news that we MIGHT need to resit BM?  |
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Nov 26 2010, 11:41 PM
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Senior Member
1,475 posts Joined: Oct 2008 From: Kuala Lumpur , MY Joined: Jan 2020
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QUOTE(abang brother @ Nov 26 2010, 11:39 PM) Ok thank you you joined LYN since Primary School? lol |
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Nov 26 2010, 11:52 PM
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Senior Member
1,372 posts Joined: Sep 2008
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QUOTE(bryanyeo @ Nov 27 2010, 12:41 AM) you joined LYN since Primary School? lol lol.. 10 years old?? salute! |
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Nov 27 2010, 12:58 AM
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Senior Member
769 posts Joined: Nov 2010
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erm erm erm.. i haven't touch physcis and addmaths yet.. and my PAi is only half way.. just finished All the Adab part and Haji .. xD.. ~
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Nov 27 2010, 01:22 AM
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Junior Member
252 posts Joined: Mar 2010
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f(x)=x-2
hf(x)=x^2+3x+1 find h(x) what is the answer? the skema gave x^2+3x+3 |
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Nov 27 2010, 01:30 AM
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Senior Member
965 posts Joined: Nov 2008
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like this mate
hf(x)=x^2+3x+1 h is x actually become h(x)-2=x^2+3x+1 h(x)=x^2+3x+3 Wallah easy |
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Nov 27 2010, 01:33 AM
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Senior Member
4,967 posts Joined: Jan 2003 From: Kuching,Sarawak Status: Same Same 
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QUOTE(bryanyeo @ Nov 26 2010, 11:41 PM) you joined LYN since Primary School? lol QUOTE(IcyDarling @ Nov 26 2010, 11:52 PM) Lol.. 10 years old?? salute! Early 2004 lol. Joined due to a game  Naz: u pro tajwid rite? Hehhe. I know how to read but dont know whats what |
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Nov 27 2010, 02:04 AM
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Junior Member
252 posts Joined: Mar 2010
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QUOTE(yoyoman @ Nov 27 2010, 01:30 AM) like this mate why i keep counting like this ..can u tell me where is my stupid mistake?lolhf(x)=x^2+3x+1 h is x actually become h(x)-2=x^2+3x+1 h(x)=x^2+3x+3 Wallah easy Attached thumbnail(s) 
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Nov 27 2010, 02:15 AM
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Senior Member
1,311 posts Joined: Nov 2006 From: peejay
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if late jangan cucuk saya.
Sejarah 2010 Answers: ABDDC/BCDBB/DDBAA/BACCD/CDBDA/CDBAC/DABCA/AACCA |
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Nov 27 2010, 02:52 AM
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Staff
2,106 posts Joined: Apr 2008 
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QUOTE(556611 @ Nov 27 2010, 02:04 AM) why i keep counting like this ..can u tell me where is my stupid mistake?lol sorry to interrupt. i stumbled upon this when i dont have anything to do.from ur assumption, y is not equal to x. so u cannot simply change h(y) to h(x) in ur two last lines. u have to change it back by using ur assumption, y=x-2 |
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Nov 27 2010, 02:53 AM
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Senior Member
1,023 posts Joined: Aug 2008
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QUOTE(fongzai92 @ Nov 27 2010, 02:15 AM) if late jangan cucuk saya. if those are the answers, the I'd get 36/40 Sejarah 2010 Answers: ABDDC/BCDBB/DDBAA/BACCD/CDBDA/CDBAC/DABCA/AACCA  |
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Nov 27 2010, 02:58 AM
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Senior Member
1,311 posts Joined: Nov 2006 From: peejay
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Congrats!
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Nov 27 2010, 02:59 AM
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Senior Member
1,023 posts Joined: Aug 2008
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QUOTE(556611 @ Nov 27 2010, 02:04 AM) why i keep counting like this ..can u tell me where is my stupid mistake?lol I'm gettin the same answer  |
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Nov 27 2010, 04:17 AM
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Senior Member
1,372 posts Joined: Sep 2008
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QUOTE(yoyoman @ Nov 27 2010, 02:30 AM) like this mate but h is outside... so h is the function and f(x) is the the variable right?hf(x)=x^2+3x+1 h is x actually become h(x)-2=x^2+3x+1 h(x)=x^2+3x+3 Wallah easy QUOTE(556611 @ Nov 27 2010, 03:04 AM) why i keep counting like this ..can u tell me where is my stupid mistake?lol i got the exact same way. where did u get the question from ? |
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Nov 27 2010, 08:27 AM
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Senior Member
2,096 posts Joined: Jan 2003
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i got x^2+7x+11 as well
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Nov 27 2010, 09:14 AM
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Junior Member
127 posts Joined: Mar 2010 
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help me this.. Find the range of values of x that satisfy both inequalities 2x^2-4x-3 ≥ x and -2<x-1<4.
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Nov 27 2010, 09:35 AM
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Senior Member
1,372 posts Joined: Sep 2008
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QUOTE(xiu lyn @ Nov 27 2010, 10:14 AM) help me this.. Find the range of values of x that satisfy both inequalities 2x^2-4x-3 ≥ x and -2<x-1<4. wat is the answer? I tried some weird methods and got 5>X ≥ 2 and 1/2 ≥ X > -1 wat i did was i found the range from the 2 equations. and then i draw it out on a line. find the intersection. But i dunno, im just trying some common sense method. is the answer right? |
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Nov 27 2010, 09:37 AM
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Senior Member
2,096 posts Joined: Jan 2003
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by the way, for the OMR papers, did you guys shade anything in for "bahasa yang digunakan"? I shaded BM for sejarah paper 1, but do you actually need to?
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Nov 27 2010, 09:37 AM
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Senior Member
1,475 posts Joined: Oct 2008 From: Kuala Lumpur , MY Joined: Jan 2020
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QUOTE(redscorpion @ Nov 27 2010, 02:52 AM) sorry to interrupt. i stumbled upon this when i dont have anything to do. Actually you can. Because the whole function is y only, is the same if you replace all y with alpha or beta or x or whatever you like. If you change it back, you can't solve it because you get h(x-2) and what you need is h(x)from ur assumption, y is not equal to x. so u cannot simply change h(y) to h(x) in ur two last lines. u have to change it back by using ur assumption, y=x-2 |
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Nov 27 2010, 10:14 AM
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Senior Member
1,372 posts Joined: Sep 2008
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QUOTE(:+:DarreN:+: @ Nov 27 2010, 10:37 AM) by the way, for the OMR papers, did you guys shade anything in for "bahasa yang digunakan"? I shaded BM for sejarah paper 1, but do you actually need to? the examiner call us to shade bahasa melayu. Just shade bah, no harm done hahaQUOTE(bryanyeo @ Nov 27 2010, 10:37 AM) Actually you can. Because the whole function is y only, is the same if you replace all y with alpha or beta or x or whatever you like. If you change it back, you can't solve it because you get h(x-2) and what you need is h(x) u are right. because the y becomes its variable. so u can change the variable in the function and change the variable in the equation too. |
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