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 -SPM Thread Version Four-, Its never too late! :)

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bryanyeo
post Nov 26 2010, 10:34 PM

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and one of the 2664 passwords is LAME
1malaysia
post Nov 26 2010, 10:36 PM

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can any1 gif the solution for the vector?
bryanyeo
post Nov 26 2010, 10:38 PM

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QUOTE(1malaysia @ Nov 26 2010, 10:36 PM)
can any1 gif the solution for the vector?
*
hard to explain so I decided not to, lol
1malaysia
post Nov 26 2010, 10:38 PM

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QUOTE(bryanyeo @ Nov 26 2010, 10:38 PM)
hard to explain so I decided not to, lol
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pls -.-


bryanyeo
post Nov 26 2010, 10:42 PM

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QUOTE(1malaysia @ Nov 26 2010, 10:38 PM)
pls -.-
*
Hope you can understand what I'm saying...

For easy understanding, draw the vector out:
draw OP, then draw OQ start from P. Then you have two lines, OP and PQ. Draw a line from O to Q, that's the vector. You should have a Triangle now if you get what I'm saying. Both line OP and PQ are 2 units.
Angle OPQ is 120 degree. Use any way you like to get the lenght for OQ.
LordReaper
post Nov 26 2010, 10:44 PM

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QUOTE(1malaysia @ Nov 26 2010, 10:38 PM)
pls -.-
*
yooo suup man ! ADD ME !
1malaysia
post Nov 26 2010, 10:45 PM

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QUOTE(bryanyeo @ Nov 26 2010, 10:42 PM)
Hope you can understand what I'm saying...

For easy understanding, draw the vector out:
draw OP, then draw OQ start from P. Then you have two lines, OP and PQ. Draw a line from O to Q, that's the vector. You should have a Triangle now if you get what I'm saying. Both line OP and PQ are 2 units.
Angle OPQ is 120 degree. Use any way you like to get the lenght for OQ.
*
how come 120 degree? i tot all angles are 60 since its a equilibrium triangle
bryanyeo
post Nov 26 2010, 10:57 PM

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Attached Image
Hope you can understand my drawing again
1malaysia
post Nov 26 2010, 10:59 PM

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QUOTE(bryanyeo @ Nov 26 2010, 10:57 PM)
Attached Image
Hope you can understand my drawing again
*
hmmm but the actual diagram is not like this. mind explain? rclxub.gif
bryanyeo
post Nov 26 2010, 11:08 PM

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QUOTE(1malaysia @ Nov 26 2010, 10:59 PM)
hmmm but the actual diagram is not like this. mind explain? rclxub.gif
*
you cant do from the original diagram, you have to draw another diagram
1malaysia
post Nov 26 2010, 11:09 PM

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QUOTE(bryanyeo @ Nov 26 2010, 11:08 PM)
you cant do from the original diagram, you have to draw another diagram
*
why ?? shocking.gif


ps: what doest | p + q | means.. distance rite?

This post has been edited by 1malaysia: Nov 26 2010, 11:11 PM
bryanyeo
post Nov 26 2010, 11:15 PM

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QUOTE(1malaysia @ Nov 26 2010, 11:09 PM)
why ?? shocking.gif
ps: what doest | p + q | means.. distance rite?
*
Attached Image


Added on November 26, 2010, 11:16 pmmeans the magnitude of the vector, for easy understanding, equals to the length

This post has been edited by bryanyeo: Nov 26 2010, 11:16 PM
1malaysia
post Nov 26 2010, 11:18 PM

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QUOTE(bryanyeo @ Nov 26 2010, 11:15 PM)
Attached Image


Added on November 26, 2010, 11:16 pmmeans the magnitude of the vector, for easy understanding, equals to the length
*
oh! we nid to get the resultant vector rite?


bryanyeo
post Nov 26 2010, 11:20 PM

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QUOTE(1malaysia @ Nov 26 2010, 11:18 PM)
oh! we nid to get the resultant vector rite?
*
yup, in short, the length of the resultant vector
1malaysia
post Nov 26 2010, 11:22 PM

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QUOTE(bryanyeo @ Nov 26 2010, 11:20 PM)
yup, in short, the length of the resultant vector
*
thx pro thumbup.gif
abang brother
post Nov 26 2010, 11:26 PM

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Hey guys. If two lines parallel but diff length, the magnitude are still the same for both lines right?
bryanyeo
post Nov 26 2010, 11:29 PM

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QUOTE(abang brother @ Nov 26 2010, 11:26 PM)
Hey guys. If two lines parallel but diff length, the magnitude are still the same for both lines right?
*
magnitude not the same. but vector 1 equals to a constant times vector 2.

So if I let k = constant, vector 1 = P , vector 2 = Q,
P = kQ
fisherman10
post Nov 26 2010, 11:34 PM

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guys!!

anyone of u got heard the news that we MIGHT need to resit BM?
abang brother
post Nov 26 2010, 11:39 PM

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QUOTE(bryanyeo @ Nov 26 2010, 11:29 PM)
magnitude not the same. but vector 1 equals to a constant times vector 2.

So if I let k = constant, vector 1 = P , vector 2 = Q,
P = kQ
*
Ok thank you smile.gif
ariff02
post Nov 26 2010, 11:40 PM

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QUOTE(fisherman10 @ Nov 26 2010, 11:34 PM)
guys!!

anyone of u got heard the news that we MIGHT need to resit BM?
*
nope , not true , confirmed

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