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 SPM Thread 08/09 (V 3), SPM is coming soon..!!!! Final days..!!

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gzavincent
post Nov 3 2008, 08:56 PM

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QUOTE(sasaug @ Nov 3 2008, 08:49 PM)
I oso hard 2 memorize that light chapter.The only topic that i am not good at in physic,others topic ok ok nia.


Added on November 3, 2008, 8:50 pmI oso hard 2 memorize that light chapter.The only topic that i am not good at in physic,others topic ok ok nia.
*
Light hardest part is the convex lens..All the image form when object place at different place..
After that nothing else...For me i think radiation is harder...
raptor_cZn
post Nov 3 2008, 09:13 PM

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QUOTE(gzavincent @ Nov 3 2008, 08:56 PM)
Light hardest part is the convex lens..All the image form when object place at different place..
After that nothing else...For me i think radiation is harder...
*
Its quite easy actually. If you can memorize the properties for concave mirror, its almost the same for convex mirror.

Radiation? Which part? Half life? That's the only part with calculations. The applications stuff is all facts.
The only other formula is E=mc^2 to calculate the energy converted from the mass defect laugh.gif


Added on November 3, 2008, 9:19 pm
QUOTE(vick5821 @ Nov 3 2008, 07:18 PM)
this i know..how abt upright? same with laterally inverted?
*
Upright means... well upright la.. the opposite for inverted (terbalik)

For laterally inverted. Take a book and put it in front of a mirror. The words in the mirror will be laterally inverted.

This post has been edited by raptor_cZn: Nov 3 2008, 09:21 PM
pwincess
post Nov 3 2008, 09:54 PM

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i wanna ask regarding probability distribution chapter.
if P(Z>Z1) use calculator to get the probability.
if P(Z<Z1) 1-value obtained from calculator
if P(Z<-Z1) use from table or wat ? cannot use like the 2nd method meh ?
fhNicK
post Nov 3 2008, 09:56 PM

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Radiation is simple to understand. Only a few formulas there and some basic facts. Keep practicing and you'll eventually get it.
And don't get nuclear fusion & fission mixed up. =D

For the probability distribution, are you referring to:
e.g. P(Z>0.5), P(Z<0.5), P(Z<-0.5)?

This post has been edited by fhNicK: Nov 3 2008, 09:58 PM
skzisghost
post Nov 3 2008, 09:57 PM

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Halp me please >.< i got no notes for bm novel and all my friend de notes is hand copy de no paper at all....what should i do now ??is there any reference book available that contain points like contoh persoalan which i can memorize ?
Kernkraft400
post Nov 3 2008, 09:58 PM

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QUOTE(pwincess @ Nov 3 2008, 09:54 PM)
i wanna ask regarding probability distribution chapter.
if P(Z>Z1) use calculator to get the probability.
if P(Z<Z1) 1-value obtained from calculator
if P(Z<-Z1) use from table or wat ? cannot use like the 2nd method meh ?
*
P(Z<-Z1) ; Means that it is P(Z > Z1 )

It is just the reverse. Since the negative value turns to be a positive value when reflected to the side of the graph.
Hope it helps.
raptor_cZn
post Nov 3 2008, 10:00 PM

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QUOTE(pwincess @ Nov 3 2008, 09:54 PM)
i wanna ask regarding probability distribution chapter.
if P(Z>Z1) use calculator to get the probability.
if P(Z<Z1) 1-value obtained from calculator
if P(Z<-Z1) use from table or wat ? cannot use like the 2nd method meh ?
*
You only need to use the table if you need to find the z-value when you are given the probability.

This post has been edited by raptor_cZn: Nov 3 2008, 10:00 PM
fhNicK
post Nov 3 2008, 10:01 PM

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QUOTE(skzisghost @ Nov 3 2008, 09:57 PM)
Halp me please >.< i got no notes for bm novel and all my friend de notes is hand copy de no paper at all....what should i do now ??is there any reference book available that contain points like contoh persoalan which i can memorize ?
*
You should be able to find reference books for the bm novel at your local bookstore. I used to buy reference books at the beginning of the year.
raptor_cZn
post Nov 3 2008, 10:01 PM

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QUOTE(raptor_cZn @ Nov 3 2008, 10:00 PM)
You only need to use the table if you need to find the z-value when you are given the probability.
*
If you can't figure things out, sketch the normal distribution graph to help you out.
pwincess
post Nov 3 2008, 10:02 PM

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QUOTE(Kernkraft400 @ Nov 3 2008, 09:58 PM)
P(Z<-Z1) ; Means that it is P(Z > Z1 )

It is just the reverse. Since the negative value turns to be a positive value when reflected to the side of the graph.
Hope it helps.
*
oh. i understand. then can obtain the value by using the distribution table is it? unsure.gif
got 1 question i didnt understand.

P(-1.3<Z<-0.9)
=Q(0.9) - Q(1.3)
=0.1814 - 0.0968
=0.0873

why 0.9-1.3 not 1.3-0.9 ? rclxub.gif

This post has been edited by pwincess: Nov 3 2008, 10:05 PM
raptor_cZn
post Nov 3 2008, 10:04 PM

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QUOTE(skzisghost @ Nov 3 2008, 09:57 PM)
Halp me please >.< i got no notes for bm novel and all my friend de notes is hand copy de no paper at all....what should i do now ??is there any reference book available that contain points like contoh persoalan which i can memorize ?
*
Well, if you know the story thoroughly then I'm pretty sure you can come up with some persoalan that are relevant.
Stuff like nilai, pengajaran, latar masyarakat are the easiest since its all based on the same nilai. Just different way of explaining and answering.
fhNicK
post Nov 3 2008, 10:06 PM

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QUOTE(pwincess @ Nov 3 2008, 10:02 PM)
oh. i understand. then can obtain the value by using the distribution table is it?  unsure.gif
got 1 question i didnt understand.

P(-1.3<Z<-0.9)
=Q(0.9) - Q(1.3)
=0.1814 - 0.0968
=0.0873

how did it get 0.9 and 1.3 ?  rclxub.gif
*
P(Z<-0.9) - P(Z<-1.3)
Look at the table for the values.
raptor_cZn
post Nov 3 2008, 10:07 PM

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QUOTE(pwincess @ Nov 3 2008, 10:02 PM)
oh. i understand. then can obtain the value by using the distribution table is it?  unsure.gif
got 1 question i didnt understand.

P(-1.3<Z<-0.9)
=Q(0.9) - Q(1.3)
=0.1814 - 0.0968
=0.0873

why 0.9-1.3 not 1.3-0.9 ?  rclxub.gif
*
You take 0.9 which represents the area from 0.9 till infinity to minus 1.3 to infinity onwards to get the area in between

You can use you calc to find the values since you are looking for the probability.

If you use Q(1.3) - Q(0.9) you will get a negative value (area)/ negative probability which is not possible.

Remember, probability must be between 0 and 1.

This post has been edited by raptor_cZn: Nov 3 2008, 10:11 PM


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pwincess
post Nov 3 2008, 10:10 PM

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oh~ i c. thx so much! smile.gif
Kernkraft400
post Nov 3 2008, 10:16 PM

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Well if you dont understand what he says, its simply because 0.9 has a bigger value in the table rather than 1.3, and also must remember that probability has a value of 0 to 1 , and it can never be negative or more than 1.

And his standard normal distribution graph is correct. From then on, you can see that 0.9 covers more area to infinity than 1.3 to infinity.

Hope this helps.
pwincess
post Nov 3 2008, 10:31 PM

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i understand. u helped alot. thank u.
an admaths question :
The mean of a set of eight positive integers is 12. When a number k is taken out from the set of numbers, its mean becomes 13. Find the number k.
katana18
post Nov 3 2008, 10:32 PM

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Heh. SPM is next week, and I'm sitting here looking up phone reviews, playing Team Fortress 2, and occasionally reading a little Sejarah.

Fun.
raptor_cZn
post Nov 3 2008, 10:35 PM

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QUOTE(pwincess @ Nov 3 2008, 10:31 PM)
i understand. u helped alot. thank u.
an admaths question :
The mean of a set of eight positive integers is 12. When a number k is taken out from the set of numbers, its mean becomes 13. Find the number k.
*
First find Sum of x which is (12)(8)

Then 13=(sum of x - k)/(7)

Ans is 5


Added on November 3, 2008, 10:41 pm
QUOTE(katana18 @ Nov 3 2008, 10:32 PM)
Heh. SPM is next week, and I'm sitting here looking up phone reviews, playing Team Fortress 2, and occasionally reading a little Sejarah.

Fun.
*
Haha.. I'm at Chapter 7 of F5 Sej now. Planning to fin by morning =p
After that, study some Komsas and lit stuff then rest my brain.

This post has been edited by raptor_cZn: Nov 3 2008, 10:43 PM
Kernkraft400
post Nov 3 2008, 10:46 PM

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Sum of original set (x)= 8x12 = 96

New mean= (96-k)/7
13 (7) = 96 - k
91 = 96 - k
-5 = -k
K = 5
TSvick5821
post Nov 3 2008, 10:48 PM


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work_tgr..how is the virtual image? still cant get la..get abit

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