lg(x+1)-lg(2x-5)=1
lg (x+1)/(2x-5) =1
(x+1)/(2x-5) = 10
x+1=20x-50
19x=51
x= 51/19

log3 (2x-1) + log3 (x-2) =1
log3 (2x-1)(x-2) = 1
(2x-1)(x-2) = 3
continue solve the quadratic formula....... lazy finish it

for mt..juz do pass year question will do...dun do other if not confuse urself..believe me

Yes I was right!

lg(x+1) - lg(2x-5) = 1
lg (x+1)/(2x-5) = lg 10^1
maka, (x+1)/(2x-5) = 10
(x+1) = 10(2x-5) = 20x-50
1+50 = 20x-x = 19x
x = 51/19 = 2.6842

log3(2x-1) = 1 - log3(x-2)
log3(2x-1) + log3(x-2) = 1
log3(2x-1)(x-2) = log3 3^1
(2x-1)(x-2) = 3
2x^2 - 4x - x + 2 - 3 = 0
2x^2 - 5x - 1 = 0
x = 2.6861 atau -0.1861

Dalam log tiada negatif, abaikan x=-0.1861
maka, x=2.6861

Anyone can help on this?

The recommended way is using pembezaan. I can do it. But I want to use the other way, using persamaan the other method to find titik maksimum in fungsi chapter. What do we call taht liao? Either my calculation is wrong or it really cant. I think can ler...



I know how to solve but I want to see if there is anyway to get the titik maksimum other than using pembezaan. Try to solve

This post has been edited by kvys2000: Nov 26 2006, 03:50 PM

log135
= log27 + log5
= log3 +log3 +log3 +log5
= log'm 3 / log'm 15 x log'm 3 / log'm 15 x log'm 3 / log'm 15 x log'm 5 / log'm 15

all the log'm 15 -> log'm 5 + log'm 3

so now u got both log'm 3 and log'm 5
change it all den...

sry if it confuse u cos i dont realli know how to write log15 and shrink the 15.. and m

aiks..passing rate is so low...dun panic guys...

u mean the wat wat ganda dua thingy? liek (x+?) + ?

guess thats penyelesaian kuasa dua...

yea yea... penyelesaian kuasa dua!~ I find the x value = 4 while using pembezaan is 2

u beza wrong la
y ' = -2 - x
m = -2
n i count again
correct
M = -2
n = 5

x=-2

This post has been edited by ptewee: Nov 26 2006, 04:17 PM

lolxxx...
y all say passing mark..
as lowyat forumers muz aim for A1 !!!!

answer is ??

er...what's the psm after pembezaan ?

ehh... beze correct, I think I provided wrong answer. I want anyone try penyelesaian ganda dua?

i want to know what's the persamaan after beze the persamaan given only >.<

use kaedah penyempurnaan kuasa

y=-0.5x^2-2x+6
=-0.5(x^2+4x-12)
=-0.5(x^2+4x+4-16)
=-0.5(x+2)^2+8

m+2=0
m=-2

8=3m^2+n
8=12+n
n=-4

err... i think i got the wrong answer... can anyone help me check and seee.......

m= -2
n= -20
(PKD way)

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