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 SPM Students Discussion Thread V3, New Thread: End of an Era!!

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DeathChaosX
post Nov 26 2006, 01:57 AM

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QUOTE(sumbody @ Nov 26 2006, 01:52 AM)
2lg2 - 2lg3 + lg21 + 2lg5 + lg21 + 2lg5 - lg7

= lg2^2 - lg3^2 + lg21 + lg5^2 + lg21 + lg5^2 - lg7

= lg4 - lg9 + lg21 + lg25 + lg21 + lg25 - lg7

*Berdasarkan Hukum Log (or something like that)

log A + log B = log AB

log A - log B = log A/B

maka

= lg [(4/9)(21)(25)(21)(25)]/7

= lg 17500

Don't know correct or not?
*
in the end also must use calc....where's the question-er?
bluhapp
post Nov 26 2006, 02:03 AM

what? i can change title now? OMG
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aiyoh.. dun post answer only ar.. post jalan too.. its a kertas 2 soalan.. need to know how to done it
sumbody
post Nov 26 2006, 02:24 AM

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bluhapp got the answers or not?
DeathChaosX
post Nov 26 2006, 02:25 AM

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my answer very got problem.

This post has been edited by DeathChaosX: Nov 26 2006, 02:32 AM
sumbody
post Nov 26 2006, 02:28 AM

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QUOTE(bluhapp @ Nov 26 2006, 01:48 AM)
Rajah 1 menunjukkan lengkung yang mempunyai  fungsi kecerunan k - 2x
dengan keadaan k adalah pemalar. Garis lurus AB ialah tangen kepada lengkung itu di titik (1,3) dan persamaan AB ialah x+ y = 4.

user posted image

Carikan
a) nilai k. . [2 markah]
b) persamaan lengkung itu. [4 markah]
c) luas kawasan berlorek . [2 markah]
can help me solve all a,b,c ? i got no idea on how to start unsure.gif
*
a) Nilai K
Fungsi Kecerunan = k - 2x
AB: y = 4 - x

k - 2x ialah kecerunan tangen
Daripada y = 4 - x, kecerunan ialah -1
maka, k - 2x = -1
(1,3) Gantikan x=1 ke dalam k - 2x
k-2(1) = -1
k = -1 + 2 = 1

b) Persamaan Lengkung
Kamirkan k - 2x untuk dapatkan persamaan lengkung
k - 2x = 1 - 2x

Kamirkan 1 - 2x
x - [(2x)^2]/2 + c
= x - x^2 + c

Gantikan (1,3) ke dalam Persamaan
y = x - x^2 + c
3 = 1 - 1^2 + c
c = 3
maka, y = x - x^2 + 3 ialah Persamaan Lengkung

c) Luas kawasan berlorek
Luas di bawah garis - Luas di bawah lengkung = Luas kawasan berlorek

Luas di bawah garis
y = 4 - x
Apabila x = 0, y = 4 - 0 = 4
A: (0,4)
Apabila y = 0, 0 = 4 - x
x = 4
B: (4,0)
Luas ialah 0.5 X 4 X 4 = 8 [Menggunakan rumus mengira luas segi tiga]

Luas di bawah kawasan berlorek
y = -x^2 + x + 3
Apabila y=0
0 = -x^2 + x + 3
Didapati x = -1.3028 atau 2.3028
Kamirkan y = -x^2 + x + 3 dengan had 0 hingga 2.3028

*I think I made some mistakes.... Shouldn't be so complicating answers

Correct me if I'm wrong

This post has been edited by sumbody: Nov 26 2006, 02:30 AM
Weng Siu
post Nov 26 2006, 03:10 AM

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all i aso duno do lo! prepare to die in addmath lu.. >.<
DJCeNa
post Nov 26 2006, 07:44 AM

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add maths is one of my worse subject ever... cant ever understand it.. maybe janjang and form4 early chapters can remember.. maybe also form5 early chapters... the rest cant remember...
tunertoobe
post Nov 26 2006, 09:18 AM

Look at all my stars!!
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Evrtime I do exercises on revision books and wanna try out my new "skill" on a real paper(the previous SPM papers), the questions are damn TWISTED!! vmad.gif

I only get 35/80 in the end for paper 1. cry.gif
Canopies
post Nov 26 2006, 10:45 AM

Look at all my stars!!
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5more days to go and we will rock the world
StratOS
post Nov 26 2006, 10:47 AM

Berries~ Mmmm~
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man.. hope add maths faster ovver.. moral also.. the rest juz relax nia.. tongue.gif
ptewee
post Nov 26 2006, 11:01 AM

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QUOTE(StratOS @ Nov 26 2006, 10:47 AM)
man.. hope add maths faster ovver.. moral also.. the rest juz relax nia.. tongue.gif
*
wah... u so pro meh?.... wad abt kim fiz and bio?
zltan
post Nov 26 2006, 11:04 AM

On my way
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I am worried about moral and the experiments. Add maths is ok to me. A lot of states spot the 'getah tervulkan' for chem and I guess the MES will change the paper. =[
ptewee
post Nov 26 2006, 11:09 AM

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hey, if everyone's here lets go to the dalnet chatroom on mirc... channel #spm2006
ffrulz
post Nov 26 2006, 11:21 AM

Over the hills and far away.
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QUOTE(ptewee @ Nov 26 2006, 11:09 AM)
hey, if everyone's here lets go to the dalnet chatroom on mirc... channel #spm2006
*
Nobody there cept you and me.
ptewee
post Nov 26 2006, 11:27 AM

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if then how to chat and discuss?? anyone free pls go in lah...
Weng Siu
post Nov 26 2006, 11:51 AM

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i do the pass year addmath question.1 hour onli done few question!swt..
lightbringer
post Nov 26 2006, 11:55 AM

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oops there is a mistake in my question, its lg3 only not 2lg3, and there is an extra lg21 also, was too hurry when im typing the question, my bad... sweat.gif

2lg2 - lg3 + lg21 + 2lg5 - lg7
= lg4 - lg3 + lg21 + lg25 - lg7
= lg(4/3 x 21 x 25/7)
= lg100
= 2

i got many more log question but i dunno how to type it here, dunno how to type the asas...

This post has been edited by lightbringer: Nov 26 2006, 11:59 AM
maniac_rage
post Nov 26 2006, 11:57 AM

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QUOTE(Weng Siu @ Nov 26 2006, 11:51 AM)
i do the pass year addmath question.1 hour onli done few question!swt..
*
Same here. I have to refer to the reference book everytime I do add maths questions.
Weng Siu
post Nov 26 2006, 12:03 PM

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QUOTE(lightbringer @ Nov 26 2006, 11:55 AM)
oops there is a mistake in my question, its lg3 only not 2lg3, and there is an extra lg21 also, was too hurry when im typing the question, my bad...  sweat.gif

2lg2 - lg3 + lg21 + 2lg5 - lg7
= lg4 - lg3 + lg21 + lg25 - lg7
= lg(4/3 x 21 x 25/7)
= lg100
= 2

i got many more log question but i dunno how to type it here, dunno how to type the asas...
*
without calculator how to do?? need use alot time to X and / to get lg100. and y ur all noe lg100 =2 ? formula?? rclxub.gif
ffrulz
post Nov 26 2006, 12:05 PM

Over the hills and far away.
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QUOTE(Weng Siu @ Nov 26 2006, 12:03 PM)
without calculator how to do?? need use alot time to X and / to get lg100. and y ur all noe lg100 =2 ? formula?? rclxub.gif
*
lg = log asas 10

lg100 = log10 100

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