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SPM Students Discussion Thread V3, New Thread: End of an Era!!
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Criptonox89
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Nov 25 2006, 11:58 PM
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4 dec man....it's close!!! Just waiting for the day....unknowningly....we had sit on the hall for 5 days....the time gone sooo fast...after the exam....full of activities....6/7/8 dec.....vocation with classmates.....9 dec...graduation night......and so on.....trip again.....relax for a month 1st....and then gonna have course....mostly for english course...
log is still ok for me....only those question in paper 2....if cannot finish A...the rest B,C all habis...
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lightbringer
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Nov 25 2006, 11:59 PM
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let me ask u all a log question
try to find the answer without using calculator
2lg2 - 2lg3 + lg21 + 2lg5 + lg21 + 2lg5 - lg7
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~~5ive~~
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Nov 26 2006, 12:13 AM
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QUOTE(lightbringer @ Nov 25 2006, 11:59 PM) let me ask u all a log question try to find the answer without using calculator 2lg2 - 2lg3 + lg21 + 2lg5 + lg21 + 2lg5 - lg7 simplify it?
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Criptonox89
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Nov 26 2006, 12:15 AM
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izzit possible to come out during SPM...?
if yes....would you be so dumb do it witout using calculator unless ask you to show the jalan kerja...
but the question is possible to do it without using calculator..? i can't do it..simplify or find the answer...?
This post has been edited by Criptonox89: Nov 26 2006, 12:16 AM
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lightbringer
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Nov 26 2006, 12:15 AM
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the answer is 2  the question ask us not to use calulator, btw lg means log asas 10 This post has been edited by lightbringer: Nov 26 2006, 12:16 AM
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Criptonox89
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Nov 26 2006, 12:16 AM
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show us the jalan kerja pls...
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~~5ive~~
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Nov 26 2006, 12:20 AM
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QUOTE(lightbringer @ Nov 26 2006, 12:15 AM) the answer is 2  the question ask us not to use calulator, btw lg means log asas 10 r u sure answer is 2?
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~~5ive~~
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Nov 26 2006, 12:21 AM
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i will be simplify it become 2lg50 + lg7
i check dy, the value is 4.243 which same with the thing u give too.... i dun think answer is 2 then...
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MohdRidhwan
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Nov 26 2006, 12:22 AM
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anyone kena NS? i kena at sibu, sarawak. 1st january ooo...hehehe
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ptewee
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Nov 26 2006, 12:34 AM
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hey guys, join in my mirc spm chat room at dalnet server. Channel: #spm2006
it will always be open for chat... 24/7 till end of spm (dats 4th dec for me)
This post has been edited by ptewee: Nov 26 2006, 12:39 AM
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~~5ive~~
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Nov 26 2006, 12:48 AM
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QUOTE(~~5ive~~ @ Nov 26 2006, 12:21 AM) i will be simplify it become 2lg50 + lg7 i check dy, the value is 4.243 which same with the thing u give too.... i dun think answer is 2 then... Hey...y no reply....confirm ur answer? this is my answer though
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ptewee
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Nov 26 2006, 12:54 AM
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they shud be sleeping
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Criptonox89
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Nov 26 2006, 12:58 AM
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QUOTE(~~5ive~~ @ Nov 26 2006, 12:48 AM) Hey...y no reply....confirm ur answer? this is my answer though i can't get answer 2 too....show us the jalan kerja la...whatever from the book or your answer.....
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~~5ive~~
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Nov 26 2006, 01:18 AM
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QUOTE(Criptonox89 @ Nov 26 2006, 12:58 AM) i can't get answer 2 too....show us the jalan kerja la...whatever from the book or your answer..... well, have to wait till tomolo i guess.....Haiz....
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DeathChaosX
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Nov 26 2006, 01:33 AM
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Getting Started

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i get until 2+lg 7+ lg25 then duno do liao
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DeathChaosX
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Nov 26 2006, 01:38 AM
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Getting Started

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=lg4-lg9+lg3+lg25+lg21+lg25 =lg100-lg9+lg3+lg7+lg3+lg25 =2-lg9+lg9+lg7+lg25 =2+lg7+lg25 =2+lg7+lg10+lg2.5 =3+lg17.5 =4+lg1.75
duno correct or not.
This post has been edited by DeathChaosX: Nov 26 2006, 01:58 AM
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bluhapp
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Nov 26 2006, 01:48 AM
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Rajah 1 menunjukkan lengkung yang mempunyai fungsi kecerunan k - 2x dengan keadaan k adalah pemalar. Garis lurus AB ialah tangen kepada lengkung itu di titik (1,3) dan persamaan AB ialah x+ y = 4.  Carikan a) nilai k. . [2 markah] b) persamaan lengkung itu. [4 markah] c) luas kawasan berlorek . [2 markah] can help me solve all a,b,c ? i got no idea on how to start This post has been edited by bluhapp: Nov 26 2006, 01:49 AM
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e30
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Nov 26 2006, 01:51 AM
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does anyone have any tips or any links to tips for pendidkan islam? please do share
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sumbody
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Nov 26 2006, 01:52 AM
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2lg2 - 2lg3 + lg21 + 2lg5 + lg21 + 2lg5 - lg7
= lg2^2 - lg3^2 + lg21 + lg5^2 + lg21 + lg5^2 - lg7
= lg4 - lg9 + lg21 + lg25 + lg21 + lg25 - lg7
*Berdasarkan Hukum Log (or something like that)
log A + log B = log AB
log A - log B = log A/B
maka
= lg [(4/9)(21)(25)(21)(25)]/7
= lg 17500
Don't know correct or not?
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DeathChaosX
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Nov 26 2006, 01:55 AM
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Getting Started

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deleted: got wrong answer.
This post has been edited by DeathChaosX: Nov 26 2006, 02:33 AM
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