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STPM 2014/2015
STPM 2014/2015
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Oct 15 2014, 09:55 PM
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Junior Member
10 posts Joined: Mar 2014 |
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Oct 15 2014, 10:39 PM
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VIP
3,713 posts Joined: Nov 2011 From: Torino |
QUOTE(yuza014 @ Oct 15 2014, 09:55 PM) Someone help me answering this.. My answer is different from the given answer.. I got 0.309 but the answer is 0.38 mole fraction.. Question number 1 Please show your workings, so that your peers can comment. |
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Oct 18 2014, 06:43 PM
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Senior Member
654 posts Joined: Apr 2013 From: Planet Earth |
Hello Just Visiting By, I have a question here to you regarding my MUET Speaking test that I took last Wednesday.
You already know that for the MUET speaking test, it consists of 2 sessions(with different questions), and I was in the first sessions. One of my seniors who took the test told us that if either one of the sessions posed an easy question, then the graded band for that question is stricter. In other words, if the question that we get is tougher, then it's easier to get a higher band. How true is that? My senior informed us that it was the third time she retake the MUET test, and that she could easily tell which is easier and which is harder. And from what I can see, there was no fraudulently whatsoever in her statement. I did checked out with my peers from the second session, and from what I've observed, the questions and even the choices for some candidates are blatantly tougher than the ones that we(first session) had. |
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Oct 18 2014, 07:21 PM
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Senior Member
654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(yuza014 @ Oct 15 2014, 09:55 PM) Someone help me answering this.. My answer is different from the given answer.. I got 0.309 but the answer is 0.38 mole fraction.. Question number 1 Weird, I got 0.309 for the mole fraction of benzene in vapour too. I too would like some clarification for this question. Where is my error? According to Raoult's law: Partial pressure of benzene: ![]() Partial pressure of methylbenzene: ![]() Total pressure, ![]() ∴Mole fraction of benzene in vapour= ![]() Critical_Fallacy, can you help us? This post has been edited by RED-HAIR-SHANKS: Oct 18 2014, 07:31 PM |
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Oct 18 2014, 09:13 PM
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Senior Member
1,846 posts Joined: May 2013 |
QUOTE(RED-HAIR-SHANKS @ Oct 18 2014, 06:43 PM) Hello Just Visiting By, I have a question here to you regarding my MUET Speaking test that I took last Wednesday. I don't know much about that, sorry.You already know that for the MUET speaking test, it consists of 2 sessions(with different questions), and I was in the first sessions. One of my seniors who took the test told us that if either one of the sessions posed an easy question, then the graded band for that question is stricter. In other words, if the question that we get is tougher, then it's easier to get a higher band. How true is that? My senior informed us that it was the third time she retake the MUET test, and that she could easily tell which is easier and which is harder. And from what I can see, there was no fraudulently whatsoever in her statement. I did checked out with my peers from the second session, and from what I've observed, the questions and even the choices for some candidates are blatantly tougher than the ones that we(first session) had. But from what I gathered, I suspect the marker is lenient if the candidates are weak, but strict if the candidates are fluent. Somehow the marks for Speaking component doesn't actually match between two who have almost equal proficiency. |
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Oct 18 2014, 10:05 PM
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Senior Member
654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(Just Visiting By @ Oct 18 2014, 09:13 PM) I don't know much about that, sorry. Alright. Dwelling on it won't add up my MUET marks, besides, I still have reading and writing which I reckon are much more crucial than speaking alone. But from what I gathered, I suspect the marker is lenient if the candidates are weak, but strict if the candidates are fluent. Somehow the marks for Speaking component doesn't actually match between two who have almost equal proficiency. And thank you again for guiding my teammates and I for our speaking preparations. Even though we did have some trouble conveying our thoughts and points during Task B, it nevertheless went quite alright. Our weekly training did ameliorate our speaking proficiency in the long run. After we did our Speaking test, one of my teammates(Candidate B) personally told me that he was able to quickly come up with new points and elaboration in his mind and spoke it out naturally without even the need to jot them down in black and white. While previously when in class, he can't even able to speak without the help of notes by his side and even when he has them, he would just literally read them out aloud. It has become a second nature to him already since we did our training. |
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Oct 18 2014, 11:33 PM
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Senior Member
846 posts Joined: Jun 2014 From: Reality-escaping 2D world |
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Oct 18 2014, 11:43 PM
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Senior Member
846 posts Joined: Jun 2014 From: Reality-escaping 2D world |
QUOTE(RED-HAIR-SHANKS @ Oct 18 2014, 08:21 PM) Weird, I got 0.309 for the mole fraction of benzene in vapour too. I too would like some clarification for this question. Where is my error? i got the same answer too, there is a huge possibility that the answers given may be wrong According to Raoult's law: Partial pressure of benzene: ![]() Partial pressure of methylbenzene: ![]() Total pressure, ![]() ∴Mole fraction of benzene in vapour= ![]() Critical_Fallacy, can you help us? we need your help Critical_Fallacy Attached thumbnail(s) |
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Oct 19 2014, 01:40 AM
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VIP
3,713 posts Joined: Nov 2011 From: Torino |
QUOTE(RED-HAIR-SHANKS @ Oct 18 2014, 07:21 PM) Weird, I got 0.309 for the mole fraction of benzene in vapour too. I too would like some clarification for this question. QUOTE(scgoh123 @ Oct 18 2014, 11:43 PM) i got the same answer too, there is a huge possibility that the answers given may be wrong I think the answer in the textbook may be wrong. |
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Oct 19 2014, 01:43 AM
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VIP
3,713 posts Joined: Nov 2011 From: Torino |
QUOTE(scgoh123 @ Oct 18 2014, 11:33 PM) can anyone help me with this? What you need to show is that the gravity g decreases with altitude h as one rises above the Earth's surface because W ∝ 1/r². From that, you can find the relationship between the gravity g at altitude h and the surface gravity g₀ (h = 0).![]() ******************************************************************** A mathematically intuitive physicist will do this, but you can skip this step if you want. ![]() ******************************************************************** The next stage is to determine the altitude that yields the percent error, δ = 1%, or the relative error, η = 0.01. The formula for relative error η is given by ![]() Applying the formula to the problem, we have ![]() So, writing the result correct to 1 significant figure h = 30 km |
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Oct 21 2014, 07:47 PM
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Senior Member
1,846 posts Joined: May 2013 |
QUOTE(RED-HAIR-SHANKS @ Oct 18 2014, 10:05 PM) Alright. Dwelling on it won't add up my MUET marks, besides, I still have reading and writing which I reckon are much more crucial than speaking alone. Glad to hear that. Happy I could help. And thank you again for guiding my teammates and I for our speaking preparations. Even though we did have some trouble conveying our thoughts and points during Task B, it nevertheless went quite alright. Our weekly training did ameliorate our speaking proficiency in the long run. After we did our Speaking test, one of my teammates(Candidate B) personally told me that he was able to quickly come up with new points and elaboration in his mind and spoke it out naturally without even the need to jot them down in black and white. While previously when in class, he can't even able to speak without the help of notes by his side and even when he has them, he would just literally read them out aloud. It has become a second nature to him already since we did our training. |
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Oct 22 2014, 05:21 PM
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Senior Member
846 posts Joined: Jun 2014 From: Reality-escaping 2D world |
QUOTE(Critical_Fallacy @ Oct 19 2014, 02:43 AM) What you need to show is that the gravity g decreases with altitude h as one rises above the Earth's surface because W ∝ 1/r². From that, you can find the relationship between the gravity g at altitude h and the surface gravity g₀ (h = 0). Thanks! I will try to understand, and I may ask you some further questions ![]() ******************************************************************** A mathematically intuitive physicist will do this, but you can skip this step if you want. ![]() ******************************************************************** The next stage is to determine the altitude that yields the percent error, δ = 1%, or the relative error, η = 0.01. The formula for relative error η is given by ![]() Applying the formula to the problem, we have ![]() So, writing the result correct to 1 significant figure h = 30 km |
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Oct 22 2014, 05:21 PM
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Senior Member
846 posts Joined: Jun 2014 From: Reality-escaping 2D world |
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Oct 22 2014, 06:17 PM
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Senior Member
654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(scgoh123 @ Oct 22 2014, 05:21 PM) Writing is mostly my main concern now. Whereas for Reading, it all boils down on my capabilities in interpreting each question and analysing the choices that I have, sometimes I lose plenty of marks due to careless mistakes. So, how was your speaking test going for you? |
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Oct 22 2014, 07:31 PM
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Senior Member
846 posts Joined: Jun 2014 From: Reality-escaping 2D world |
QUOTE(RED-HAIR-SHANKS @ Oct 22 2014, 07:17 PM) Writing is mostly my main concern now. Whereas for Reading, it all boils down on my capabilities in interpreting each question and analysing the choices that I have, sometimes I lose plenty of marks due to careless mistakes. My teacher adviced me that my English standard has to be improved and she told me that I am not prepared to take MUET exam this November.So, how was your speaking test going for you? By the way, I have undergone certain trials and my overall grade for Speaking was only 24 out of 45! Terrible isn't it? Luckily I did not take MUET exam this time. I think when comes to speaking, i will get panic and nervous easily because I am not used to speak in front of people. My writing sucks too. 51/90. How do you ”squeeze" out those uncommonly used phrasal words? I am eager to know. This post has been edited by scgoh123: Oct 23 2014, 02:57 PM |
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Oct 22 2014, 08:48 PM
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Junior Member
15 posts Joined: Sep 2014 |
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Oct 22 2014, 10:47 PM
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Junior Member
150 posts Joined: Feb 2014 |
QUOTE(scgoh123 @ Oct 11 2014, 06:51 PM) RED-HAIR-SHANKS I am really appreciative of your effort in sharing with us your trial papers. I am going to share some Trial papers for Physics: [attachmentid=4167033][attachmentid=4167032][attachmentid=4167031] This is my school's paper: [attachmentid=4167079] [attachmentid=4167081] However , there's no answer for the objective questions of your school trial paper. Would you kindly please upload them for me ? Thank you so much , it's really helpful! |
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Oct 23 2014, 02:56 PM
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Senior Member
846 posts Joined: Jun 2014 From: Reality-escaping 2D world |
QUOTE(daehii @ Oct 22 2014, 09:48 PM) As for the first part, Firstly, you should know the formula to calculate the concentration of OH- ions. Secondly, the concentration of aqueous ammonia varies with volume so you should take note of that. But for second part..... I am not sure. RED-HAIR-SHANKS Critical_Fallacy Can you please check for me whether my answer is correct or not. |
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Oct 23 2014, 03:54 PM
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Senior Member
654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(scgoh123 @ Oct 23 2014, 02:56 PM) But for second part..... I am not sure. I'm sorry, I'm not quite sure on how to solve the second part of the question too. RED-HAIR-SHANKS Critical_Fallacy Can you please check for me whether my answer is correct or not. While we're on it, for the first part of the question, can we use the Henderson−Hasselbalch equations too if given the fact that we know the concentration of the salt and base for that reaction? Thanks in advance. This post has been edited by RED-HAIR-SHANKS: Oct 23 2014, 03:55 PM |
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Oct 23 2014, 04:05 PM
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Senior Member
654 posts Joined: Apr 2013 From: Planet Earth |
Critical_Fallacy, can you help me with this question?
Question: An object is thrown at an angle to the horizontal with a parabolic trajectory. PQRST is part of the trajectory with P as the starting point and T as the maximum point. If every two adjacent points have the same time interval, hence the displacements PQ, QR, RS, and ST A: are the same B: increase at a fixed rate C: decrease at a fixed rate D: have the same horizontal component The answer for it is D. −I used the formula of s=vt, and I find out that the horizontal displacements,s, for every 2 adjacent points are constant due to the fact that time intervals, t=constant, and the horizontal velocity, v=constant too. But, from the choices above, how do I distinguish the answers between A and D? They carry nearly the same meaning meaning, don't they? This post has been edited by RED-HAIR-SHANKS: Oct 23 2014, 04:08 PM |
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