These weights are usually based upon expenditure data obtained from percentage of your family's monthly expenditure in Part 2 (a). You can also compare your weights with the estimates of the composition of consumption expenditure in the Consumer Price Index Malaysia April 2013 (Updated: 22/5/2013). Then, make a conclusion about your family's expenditure based on these findings.

Learning math should be fun and engaging. So, Be CREATIVE!

“Oh! senangnya, senangnya logaritma...”

That's Hydrocarbon Cracking.

Alright! I decided to release the sample answer for the final section of ADDITIONAL MATHEMATICS PROJECT WORK 1/2013 (Selangor). If you want to use this work to create remarkable web or blog content that is useful and interesting, please be kind to give due credit to the contributor who wrote it.

[1] The image of the tree is obtained from Udemy.com.
[2] The image of the archer is one of the Uberheros called Yumiyacha that appear in Patapon 3.

Hi Hanu,

I'm afraid I don't have the sample answer that you requested, but you probably can get it somewhere or do the project together with your classmates. If worse comes to worst, post your query here for discussion, and you most likely will get good responses from the Good Samaritan.

Perhaps you are not familiar with the one of the Pythagorean trigonometric identities:

sec² x = 1 + tan² x

because substituting that, you have

2 – sec² x = 2 – (1 + tan² x) = 1 – tan² x

so that the entire expression can be reduced using double-angle formula

2 tan x
------------ = tan (2x)
1 – tan² x

What's the excellence program all about?

This requires implicit proof as shown below because you can guess some people are also. However, music plus forgiveness can lessen its grip on you and help you focus on trigonometry. Good luck!

I'm sure you solve this kind of problem using simple logic.

Given that the maximum gradient of the dome the bird can only keep its balance is ±2 (left & right sides).

STEP 1 :: UNDERSTANDING THE PROBLEM

Here is the actual equation of the dome that represents the the top part (positive-y) of an ellipse

y = √[20 − (4/125)*x²]

which can be simplified to

4x² + 125y² = 2500 ... (because it is easier to differentiate it)

STEP 2 :: DEVISING A PLAN

So, d/dx (4x² + 125y² = 2500), we have

8x + 250y*y' = 0

which can be rearranged to

y' = −4x / 125y

Because the gradient y' = 2 (left side of the dome), we can rearrange 2 = −4x / 125y to

y = −4x / 250 ... (a straight line)

STEP 3 :: CARRYING OUT THE PLAN

To find the coordinates that represent the max distance the bird can walk without slipping downwards, we equate

√[20 − (4/125)*x²] = −4x / 250

Solve for x, we obtain

x = −24.901 (approx.)

To find y, we evaluate

y = −4*(−24.901) / 250 = 0.398416

STEP 4 :: LOOKING BACK

We counter-check the result if it satisfies the dome equation 4x² + 125y² = 2500.

4*(24.901)² + 125*(0.398416)² = 2500 (approx.)

Therefore, in the 2D space representation of the dome, the bird can walk up to the following coordinates without slipping downwards:

Left side of the dome, pL = (−24.901, 0.398416)
Right side of the dome, pR = (24.901, 0.398416)

You have a point and there is a numerical solution. The working of solution is all very straightforward even if it is a parabolic dome. However, without the actual graphical representation of the parabolic dome from maximR, I cannot validate the logicality of my result.

Here I'm trying to imagine the construction of the BASE of parabolic dome with radius 25 units. In construction, we usually specify the radius of the dome roof of a storage tank at the base of the dome. How do you feel we should address this?



Parabolic Dome


Elliptical Dome


Two storage tanks with dome roofs


This post has been edited by Critical_Fallacy: Jul 9 2013, 01:44 AM

f(x) = x² + 3

Because the volume of the solid formed by rotating the line segment around y-axis, you need to convert f(x) to g(y).

The volume of the solid of revolution = π ∫ [g(y)]² dy

So, do you have any idea?

Here is the sequence, but you do the maths.

3, 5, 7, 9, 11, 13, 15, 17, 19

Hi jonoave,

This is related to the Additional Mathematics Project Work 2013 (Penang).

As a seasoned biologist, could you advise me as to counting individual plant effectlively in swad of Mimosa pudica (see pics) using quadrat sampling technique, without digging up the roots?

Are the plants that touch the edge of the quadrat counted “in” or “out”?

Thanks for your explanation.

Actually, I'm having trouble to do the plant count. Shall I identify the individual plant by the primary stem? (See Table 1).

Because my cousin asked for the practical advice in counting individual plant from a swad of Mimosa pudica. Thanks, anyway!

Maybe this would help you.

So your cheat mechanism on Paper 1 is highly dependent on 3 factors:

(1) Your ability to recognize your friend's handwriting and answer within a close radius with a narrow adjacent field,
(2) a smart friend who excels in Add Maths and with good systematic workings of solutions,
(3) and whether or not you had the chance to cheat.

Thanks for keeping your promise!

I'd probably choose FUNCTIONS for 3 reasons.

(1) I like to solve puzzles.
(2) It's good to make a family history book.
(3) I'm pretty good at Paper Engineering too, where I like to make musical origami cards in my leisure time and give my loved ones, friends and family a keepsake they will treasure for life.

If you want to compare the answers for some of the mathematical problems, please let me know.

Sure! What are the first things you need to take care of? Recall from your studies, revision exercise, and SPM Add Maths Textbook!