sorry arh, the question abit different.
step 2 i dont understand.
Attached image(s)
SPM Thread 08/09 (V 3), SPM is coming soon..!!!! Final days..!!
|
|
Nov 2 2008, 11:15 PM
|
![]() ![]() ![]() ![]()
Senior Member
546 posts Joined: Nov 2007 From: Home |
i post up the solution, you explain alright x)
sorry arh, the question abit different. step 2 i dont understand. Attached image(s) |
|
|
|
|
|
Nov 2 2008, 11:17 PM
|
![]() ![]() ![]() ![]() ![]() ![]()
Senior Member
1,424 posts Joined: Sep 2007 From: Woodlands, Singapore |
QUOTE(SticH @ Nov 2 2008, 11:13 PM) Your friend pretty anot? If pretty then I'll try my best lol. Intergration must expand it wad..Worst case scenario, Expand the top equation, then seperate them and start intergrating P.s: My top method is wrong, I think. Best is do by the 2nd method. U dun expand cant do.. |
|
|
Nov 2 2008, 11:46 PM
|
![]() ![]() ![]() ![]() ![]()
Senior Member
823 posts Joined: Apr 2005 |
nvm
This post has been edited by Leto Kynes: Nov 2 2008, 11:50 PM |
|
|
Nov 2 2008, 11:50 PM
|
![]() ![]() ![]()
Junior Member
452 posts Joined: Oct 2008 From: ChocoLand |
This is the integration I've been wanting to know how to do.
Any experts? |
|
|
Nov 3 2008, 12:03 AM
|
![]() ![]() ![]() ![]() ![]() ![]()
Senior Member
1,232 posts Joined: Dec 2005 |
OMG! I had a bad time typing equations in microsoft word... just so mafan and hard to type. Someone guide me with it!
Anyways, I hope the solution below is correct. PS: Your recent posted image is not the same as the one you give initially. The 2nd one is definite integration... this one is indefinite. Added on November 3, 2008, 12:37 am@Shenay, I'm not getting the same answer as the solution posted btw... for step 2 I get: 2 [ (x^2 - x^3) / ( 3(1-3x) ) ] Added on November 3, 2008, 12:45 am QUOTE(gzavincent @ Nov 2 2008, 11:17 PM) Not necessary, if the equation is up to a power of 3 and more how are you going to expand? It's going to be a hella long to do that.there is a formula for this particular case. This post has been edited by Zepx: Nov 3 2008, 12:45 AM Attached thumbnail(s) |
|
|
Nov 3 2008, 12:49 AM
|
![]() ![]() ![]() ![]() ![]() ![]()
Senior Member
1,404 posts Joined: Feb 2006 From: KL |
QUOTE(Shenay @ Nov 2 2008, 10:51 PM) sejarah ~ killing me Try expanding it first then only integrate.Added on November 2, 2008, 10:53 pm(x-1)^2 / (3-2x)^2 . how do you intergrate this ya? Added on November 3, 2008, 12:54 am QUOTE(Zepx @ Nov 3 2008, 12:03 AM) OMG! I had a bad time typing equations in microsoft word... just so mafan and hard to type. Someone guide me with it! Didn't know you could do that. So you treat the stuff in the bracket as one whole term?Anyways, I hope the solution below is correct. PS: Your recent posted image is not the same as the one you give initially. The 2nd one is definite integration... this one is indefinite. Added on November 3, 2008, 12:37 am@Shenay, I'm not getting the same answer as the solution posted btw... for step 2 I get: 2 [ (x^2 - x^3) / ( 3(1-3x) ) ] Added on November 3, 2008, 12:45 am Not necessary, if the equation is up to a power of 3 and more how are you going to expand? It's going to be a hella long to do that. there is a formula for this particular case. This post has been edited by raptor_cZn: Nov 3 2008, 12:54 AM |
|
|
|
|
|
Nov 3 2008, 01:37 AM
|
![]() ![]() ![]()
Junior Member
452 posts Joined: Oct 2008 From: ChocoLand |
» Click to show Spoiler - click again to hide... « I don't think you can do that Lets say integrate 2x-3x2 Your method 2x-3x2 = x(2-3x) = (x2/2)(2x- 3x2/2) = x3 - 3x4/4 Correct method 2x-3x2 = x2 - x3 |
|
|
Nov 3 2008, 06:52 AM
|
![]() ![]() ![]() ![]() ![]() ![]()
Senior Member
1,232 posts Joined: Dec 2005 |
QUOTE(HotChocolate @ Nov 3 2008, 01:37 AM) » Click to show Spoiler - click again to hide... « I don't think you can do that Lets say integrate 2x-3x2 Your method 2x-3x2 = x(2-3x) = (x2/2)(2x- 3x2/2) = x3 - 3x4/4 Correct method 2x-3x2 = x2 - x3 instead i get x2 - x3 You can directly integrate the x2 - x3 and no, you cannot remove x as a common factor. why? because you are integrating dx. if you do that, meaning x is take out of the integration, in the end, you still have x. ------------- raptor_cZn, You can try expanding the equation and then integrate it. It comes to the same as mine. And yes, it's under our syllabus to take the whole bracket as one whole thing and integrate it. Alternatively, you represent 1-3x = u 1/u2 or something like tat. Added on November 3, 2008, 6:56 amOh ya, to add, for thins like (3-1x)3 there is a formula for this. (ax-b)n+1 / (dy(ax-b)/dx * n+1) Meaning, I should get: (3-1x)4/(-1 * 4) (3-1x)4/-4 Please check your book in reference to this. I'm not using anything out of syllabus. This post has been edited by Zepx: Nov 3 2008, 06:56 AM |
|
|
Nov 3 2008, 07:46 AM
|
![]() ![]() ![]() ![]() ![]()
Senior Member
874 posts Joined: Feb 2008 |
why need to factorise to make ur life harder leh =_=
just intergrate the simple equation? i think hot choc get it right |
|
|
Nov 3 2008, 11:17 AM
|
![]() ![]() ![]() ![]() ![]() ![]()
Senior Member
1,232 posts Joined: Dec 2005 |
Zzz.... please read my equations closely. Since when did I factorise the x out? I'm doing the normal way.
Either way, from my friends, point of view, there is no solution for this equation. It is not possible to integrate as the combination of nominator and denominator especially when the denominator is powered by 2. |
|
|
Nov 3 2008, 11:49 AM
|
![]() ![]() ![]()
Junior Member
452 posts Joined: Oct 2008 From: ChocoLand |
What I meant was, you seperated it out.
So, I did the same with another example. Your Solution (2x-3x2)/(1-3x)2 = (2x-3x2)(1-3x)-2 (Here you make it into multiply) = (x2-x3)[(1-3x)-1/3] (Here you differentiated separately.) My example 2x-3x2 = x(2-3x) (Here I factorise it, also means i make it into multiply) = (x2/2)(2x- 3x2/2) (Here I differentiated separately) = x3 - 3x4/4 (Here my answer is wrong.) |
|
|
Nov 3 2008, 01:17 PM
|
![]() ![]()
Junior Member
200 posts Joined: Oct 2007 |
got admaths question that needs to be solved.
The velocity, v of a particle which moves along a straight line, t seconds after passing a fixed point O, is given by v=10t-3t2+8. Find the interval from the instant the particle starts until it is instantaneously at rest. |
|
|
Nov 3 2008, 01:55 PM
|
![]() ![]() ![]() ![]()
Senior Member
546 posts Joined: Nov 2007 From: Home |
pwincess, is the answer 4s ?
|
|
|
|
|
|
Nov 3 2008, 02:04 PM
|
![]() ![]()
Junior Member
200 posts Joined: Oct 2007 |
yep. how did u do it?
can u show the calculation ? |
|
|
Nov 3 2008, 02:07 PM
|
![]() ![]() ![]() ![]()
Senior Member
546 posts Joined: Nov 2007 From: Home |
okie you see ya, when there's this word, "instantaneously at rest" means v=0. cause at rest velocity is zero. take the V equation, and equate it to zero.
v= 10t-3t2+8 = 0, and then factorize and get two answers. you will get -3/2 and 4. since its time, so yeah the first answer is not accepted =) |
|
|
Nov 3 2008, 02:17 PM
|
![]() ![]()
Junior Member
200 posts Joined: Oct 2007 |
i c. thx for the explaination ! ;D
Added on November 3, 2008, 2:29 pmbtw, how to score high marks on bm and english essay ? This post has been edited by pwincess: Nov 3 2008, 02:29 PM |
|
|
Nov 3 2008, 02:36 PM
|
![]() ![]() ![]() ![]() ![]()
Senior Member
785 posts Joined: May 2007 |
QUOTE(Shenay @ Nov 2 2008, 11:15 PM) i post up the solution, you explain alright x) I suspect there is a proving question on differentiation before doing this integration. Or else, straight-away integration for this expression is beyond SPM level.sorry arh, the question abit different. step 2 i dont understand. Mind posting the proving question? It helps a lot for this question. |
|
|
Nov 3 2008, 02:42 PM
|
![]() ![]() ![]() ![]()
Senior Member
546 posts Joined: Nov 2007 From: Home |
haha ken, yes i got it already ><
its a proving question. but i was just wondering is there, a way to intergrate without proving =) |
|
|
Nov 3 2008, 02:47 PM
|
![]() ![]()
Junior Member
95 posts Joined: Oct 2008 |
Hello
i just want to ask is there any way to intergrate this?? 3x²+2x+15 -------------- (1+3x)² |
|
|
Nov 3 2008, 03:11 PM
|
![]() ![]() ![]() ![]() ![]()
Senior Member
785 posts Joined: May 2007 |
QUOTE(Shenay @ Nov 3 2008, 02:42 PM) haha ken, yes i got it already >< I have literally banged my head on this. The expression is integratable, only with technique beyond SPM. Even so, the upper and lower limits cannot fit into the integration. its a proving question. but i was just wondering is there, a way to intergrate without proving =) In short, no straight-away integration for this question. QUOTE(Jojos @ Nov 3 2008, 02:47 PM) Feel the horror of mathematics! MUAHAHAHAHAIt's beyond SPM level. |
|
Topic ClosedOptions
|
| Change to: | 0.0204sec
0.57
6 queries
GZIP Disabled
Time is now: 19th December 2025 - 02:00 PM |