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 SPM Thread 08/09 (V 3), SPM is coming soon..!!!! Final days..!!

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Shenay
post Nov 2 2008, 11:15 PM

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i post up the solution, you explain alright x)
sorry arh, the question abit different.
step 2 i dont understand.




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gzavincent
post Nov 2 2008, 11:17 PM

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QUOTE(SticH @ Nov 2 2008, 11:13 PM)
Your friend pretty anot? If pretty then I'll try my best lol.
Worst case scenario,
Expand the top equation, then seperate them and start intergrating
P.s: My top method is wrong, I think. Best is do by the 2nd method.
*
Intergration must expand it wad..
U dun expand cant do..
Leto Kynes
post Nov 2 2008, 11:46 PM

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nvm

This post has been edited by Leto Kynes: Nov 2 2008, 11:50 PM
HotChocolate
post Nov 2 2008, 11:50 PM

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This is the integration I've been wanting to know how to do.
Any experts?
Zepx
post Nov 3 2008, 12:03 AM

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OMG! I had a bad time typing equations in microsoft word... just so mafan and hard to type. Someone guide me with it!

Anyways, I hope the solution below is correct.

PS: Your recent posted image is not the same as the one you give initially. The 2nd one is definite integration... this one is indefinite.


Added on November 3, 2008, 12:37 am@Shenay,

I'm not getting the same answer as the solution posted btw... for step 2 I get:

2 [ (x^2 - x^3) / ( 3(1-3x) ) ]


Added on November 3, 2008, 12:45 am
QUOTE(gzavincent @ Nov 2 2008, 11:17 PM)
Intergration must expand it wad..
U dun expand cant do..
*
Not necessary, if the equation is up to a power of 3 and more how are you going to expand? It's going to be a hella long to do that.

there is a formula for this particular case.

This post has been edited by Zepx: Nov 3 2008, 12:45 AM


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raptor_cZn
post Nov 3 2008, 12:49 AM

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QUOTE(Shenay @ Nov 2 2008, 10:51 PM)
sejarah ~ killing me  sad.gif


Added on November 2, 2008, 10:53 pm(x-1)^2 / (3-2x)^2 . how do you intergrate this ya?
*
Try expanding it first then only integrate.


Added on November 3, 2008, 12:54 am
QUOTE(Zepx @ Nov 3 2008, 12:03 AM)
OMG! I had a bad time typing equations in microsoft word... just so mafan and hard to type. Someone guide me with it!

Anyways, I hope the solution below is correct.

PS: Your recent posted image is not the same as the one you give initially. The 2nd one is definite integration... this one is indefinite.


Added on November 3, 2008, 12:37 am@Shenay,

I'm not getting the same answer as the solution posted btw... for step 2 I get:

2 [ (x^2 - x^3) / ( 3(1-3x) ) ]


Added on November 3, 2008, 12:45 am

Not necessary, if the equation is up to a power of 3 and more how are you going to expand? It's going to be a hella long to do that.

there is a formula for this particular case.
*
Didn't know you could do that. So you treat the stuff in the bracket as one whole term?

This post has been edited by raptor_cZn: Nov 3 2008, 12:54 AM
HotChocolate
post Nov 3 2008, 01:37 AM

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I don't think you can do that
Lets say integrate 2x-3x2

Your method
2x-3x2
= x(2-3x)
= (x2/2)(2x- 3x2/2)
= x3 - 3x4/4

Correct method

2x-3x2
= x2 - x3
Zepx
post Nov 3 2008, 06:52 AM

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QUOTE(HotChocolate @ Nov 3 2008, 01:37 AM)
» Click to show Spoiler - click again to hide... «


I don't think you can do that
Lets say integrate 2x-3x2

Your method
2x-3x2
= x(2-3x)
= (x2/2)(2x- 3x2/2)
= x3 - 3x4/4

Correct method

2x-3x2
= x2 - x3
*
I didn't get x3 - 3x4/4

instead i get x2 - x3

You can directly integrate the x2 - x3

and no, you cannot remove x as a common factor. why? because you are integrating dx. if you do that, meaning x is take out of the integration, in the end, you still have x.


-------------

raptor_cZn,

You can try expanding the equation and then integrate it. It comes to the same as mine. And yes, it's under our syllabus to take the whole bracket as one whole thing and integrate it. Alternatively, you represent

1-3x = u
1/u2

or something like tat.


Added on November 3, 2008, 6:56 amOh ya, to add,

for thins like

(3-1x)3

there is a formula for this.

(ax-b)n+1 / (dy(ax-b)/dx * n+1)

Meaning, I should get:

(3-1x)4/(-1 * 4)
(3-1x)4/-4

Please check your book in reference to this. I'm not using anything out of syllabus.

This post has been edited by Zepx: Nov 3 2008, 06:56 AM
wreckens15
post Nov 3 2008, 07:46 AM

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why need to factorise to make ur life harder leh =_=
just intergrate the simple equation?
i think hot choc get it right
Zepx
post Nov 3 2008, 11:17 AM

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Zzz.... please read my equations closely. Since when did I factorise the x out? I'm doing the normal way.

Either way, from my friends, point of view, there is no solution for this equation. It is not possible to integrate as the combination of nominator and denominator especially when the denominator is powered by 2.
HotChocolate
post Nov 3 2008, 11:49 AM

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What I meant was, you seperated it out.
So, I did the same with another example.

Your Solution
(2x-3x2)/(1-3x)2
= (2x-3x2)(1-3x)-2 (Here you make it into multiply)
= (x2-x3)[(1-3x)-1/3] (Here you differentiated separately.)

My example
2x-3x2
= x(2-3x) (Here I factorise it, also means i make it into multiply)
= (x2/2)(2x- 3x2/2) (Here I differentiated separately)
= x3 - 3x4/4 (Here my answer is wrong.)
pwincess
post Nov 3 2008, 01:17 PM

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got admaths question that needs to be solved. icon_question.gif

The velocity, v of a particle which moves along a straight line, t seconds after passing a fixed point O, is given by v=10t-3t2+8. Find the interval from the instant the particle starts until it is instantaneously at rest.
Shenay
post Nov 3 2008, 01:55 PM

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pwincess, is the answer 4s ?
pwincess
post Nov 3 2008, 02:04 PM

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yep. how did u do it?
can u show the calculation ? smile.gif
Shenay
post Nov 3 2008, 02:07 PM

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okie you see ya, when there's this word, "instantaneously at rest" means v=0. cause at rest velocity is zero. take the V equation, and equate it to zero.

v= 10t-3t2+8 = 0, and then factorize and get two answers.
you will get -3/2 and 4. since its time, so yeah the first answer is not accepted =)
pwincess
post Nov 3 2008, 02:17 PM

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i c. thx for the explaination ! ;D


Added on November 3, 2008, 2:29 pmbtw, how to score high marks on bm and english essay ?

This post has been edited by pwincess: Nov 3 2008, 02:29 PM
IamjustME
post Nov 3 2008, 02:36 PM

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QUOTE(Shenay @ Nov 2 2008, 11:15 PM)
i post up the solution, you explain alright x)
sorry arh, the question abit different.
step 2 i dont understand.
*
I suspect there is a proving question on differentiation before doing this integration. Or else, straight-away integration for this expression is beyond SPM level.

Mind posting the proving question? It helps a lot for this question.





Shenay
post Nov 3 2008, 02:42 PM

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haha ken, yes i got it already ><
its a proving question.
but i was just wondering is there, a way to intergrate without proving =)
Jojos
post Nov 3 2008, 02:47 PM

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Hello smile.gif

i just want to ask
is there any way to intergrate this??


3x²+2x+15
--------------
(1+3x)²


IamjustME
post Nov 3 2008, 03:11 PM

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QUOTE(Shenay @ Nov 3 2008, 02:42 PM)
haha ken, yes i got it already ><
its a proving question.
but i was just wondering is there, a way to intergrate without proving =)
*
I have literally banged my head on this. The expression is integratable, only with technique beyond SPM. Even so, the upper and lower limits cannot fit into the integration.

In short, no straight-away integration for this question.


QUOTE(Jojos @ Nov 3 2008, 02:47 PM)
Hello smile.gif

i just want to ask
is there any way to intergrate this??
3x²+2x+15
--------------
  (1+3x)²
*
Feel the horror of mathematics! MUAHAHAHAHA

It's beyond SPM level.


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