QUOTE(jojolicia @ Aug 10 2023, 08:55 PM)
Yes
But sometime really bad luck
Now i stop and thinl other high chance way
Probability of winning on 1-18 but losing on Even:
This situation occurs when the ball lands on a number between 1 and 18 (inclusive), but the number is odd.
To calculate this probability, we need to find the probability of landing on 1-18 and multiply it by the probability of landing on an odd number.
Since there are 18 numbers in 1-18 and 9 odd numbers, the probability is (18/37) * (9/18) โ 0.1246 or
approximately 12.46%.
Probability of both 1-18 and Even winning:
This outcome happens when the ball lands on a number between 1 and 18 (inclusive) and the number is also even.
The probability can be calculated by multiplying the probability of landing on 1-18 by the probability of landing on an even number.
So, (18/37) * (9/18) โ 0.2373 or
approximately 23.73%.
Probability of both 1-18 and Even losing:
In this case, the ball doesn't land on a number between 1 and 18 (inclusive), and it's also an odd number.
To find this probability, we calculate the complement of the sum of the probabilities from the first two situations. So,
1 - (0.1246 + 0.2373)
โ 0.2474 or
approximately 24.74%.
Probability of winning on 1-18 but losing on Even: 12.46%
Probability of both 1-18 and Even winning: 23.73%
Probability of both 1-18 and Even losing: 24.74%
Probability of the ball landing on the green zero: 2.70%
The sum of these probabilities is:
12.46% + 23.73% + 24.74% + 2.70%
= 63.63%
Therefore, the missing percentage is: 100% - 63.63%
= 36.37%.
The probability of the ball landing on the green zero (0) is 2.70%.
The sum of the probabilities of all outcomes (winning on 1-18 but losing on Even, both 1-18 and Even winning, both 1-18 and Even losing, and landing on the green zero) is 63.63%.
The remaining percentage (100% - 63.63%) is 36.37%, which represents the chance of losing in various scenarios.
Correct?
This post has been edited by plouffle0789: Aug 10 2023, 09:10 PM