Hi everyone,: ),I am new here!!!!! Can somebody add me in the list of SPM 2013 candidates,btw I am a pure science student,9 subjects
SPM 2013 Thread
SPM 2013 Thread
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Apr 10 2013, 07:49 PM
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#1
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654 posts Joined: Apr 2013 From: Planet Earth |
Hi everyone,: ),I am new here!!!!! Can somebody add me in the list of SPM 2013 candidates,btw I am a pure science student,9 subjects
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Apr 30 2013, 08:09 PM
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#2
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654 posts Joined: Apr 2013 From: Planet Earth |
I reckon you to focus on all the vital points(isi) in each subtopic that you have learnt by doing short notes,especially the ones that are gonna come out in the essay questions. After you have memorized all the points, then you should try out some exercise to refresh the information that you've stored in your brain. Btw,its a really good idea to refer to textbook than rely on your revision book,and doing SHORT NOTES really does help you if you're coerced to doing last minutes revision,GUD LUCK!!!!
This post has been edited by RED-HAIR-SHANKS: Apr 30 2013, 08:10 PM |
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May 1 2013, 10:29 AM
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#3
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654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(manutd96 @ May 1 2013, 01:40 AM) As you can clearly see,the arrangement of the bulbs A,B and bulb C is in parallel form. This is due to the fact that the current that flows from the anode has two pathways to reach the cathode: --->the 1st pathway is through bulb A ---> the 2nd pathway is through bulb B and C,which is connected in series. And as you can see,bulb D is arranged in series form that has been separated from the others bulbs,so bulb D will light up the brightest. Let me briefly explain as to why bulb D in series form is the brightest: side notes: I=current Let's say bulb A=Ia bulb B=Ib bulb C=Ic bulb D=Id As I said earlier, bulb A,B and C is branched in parallel form,but bulb B and C is arranged in series form. So,the total current flows in parallel is: I(total)=[Ib=Ic]+Ia Hence,the current supplied by the battery is as same as [Ib=Ic]+Ia Since bulb D is in series,its current will be as same as the total current supplied by the battery,which also means that: I(total current supplied by battery) = [Ib=Ic]+Ia = Id As you can see,you can roughly estimate that the value of Id is much larger than Ia,Ib or Ic. And since the brightness of the bulb depends on the current,it can be concluded that bulb D glows the brightest,since its current is the highest among all of the bulbs. I had done several questions that were as same as this,so I am quite sure that my theory is correct,if it is wrong,then kindly correct me. Hope you fathom the explanation. This post has been edited by RED-HAIR-SHANKS: May 1 2013, 10:35 AM |
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May 1 2013, 10:46 AM
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#4
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654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(Critical_Fallacy @ Apr 30 2013, 11:43 PM) I generally enjoy Numerical Methods. You learned Newton–Raphson method the other day. It’s a powerful technique for solving equations numerically. Numerical methods are techniques by which mathematical problems are formulated so that they can be solved with arithmetic operations. They are extremely powerful problem-solving tools. And they are capable of handling large systems of equations, nonlinearities, and complicated geometries that are not uncommon in engineering practice and that are often impossible to solve analytically. As such, they greatly enhance your problem-solving skills. |
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May 1 2013, 01:37 PM
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#5
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QUOTE(darrenliew96 @ May 1 2013, 12:14 PM) Because all the circuit current must pass through there. Yes,you're correct Btw, another addmath question again ![]() Please attach working and explanation please. This post has been edited by RED-HAIR-SHANKS: May 1 2013, 01:42 PM |
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May 1 2013, 02:30 PM
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#6
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654 posts Joined: Apr 2013 From: Planet Earth |
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May 1 2013, 02:54 PM
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#7
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QUOTE(Critical_Fallacy @ May 1 2013, 02:27 PM) Please complete TASK 3. Read the instruction carefully (especially the last 3 words) and refer to your textbook. Think correctly, but don't solve. Show me the formula first. You probably won't understand even if others give you the formula straightaway. You need to comprehend the first time for yourself. Have you ever noticed either ∫ f(x) dx or ∫ g(y) dy? The integral ∫ g(y) dx in your case is invalid. This post has been edited by RED-HAIR-SHANKS: May 1 2013, 02:55 PM |
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May 17 2013, 04:25 PM
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#8
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654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(x3cream @ May 16 2013, 08:06 PM) Well, I certainly distaste my performance in this mid-year exam. I did lots of awful flaws and I even made several silly mistakes where I shouldn't This post has been edited by RED-HAIR-SHANKS: May 17 2013, 04:25 PM |
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May 20 2013, 03:38 PM
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#9
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654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(ILECHZ @ May 19 2013, 05:09 PM) Guys really need help i having my SPMU on 12 June For BM Yet I still dont know what to study. can anyone give me some tips on what part to learn? Well, I reckon you to revise on essay (karangan fakta), which is the 'Belly of The Beast' for BM, if not most. You see, if you could wisely find several points (isi-isi penting) or perhaps surf online and ask Mr.Google regarding the tips on how to write pendahuluan, isi or kesimpulan regarding any essay that you favour, you could simply master it without any coercion. For example, you can try to get as many points as you like regarding karangan that sounds like these : 'kesan-kesan penyalahgunaan dadah' , ' kesan-kesan pencemaran alam sekitar' and etc. If you're able to relate the subjects(person/people) into the karangan, for example: pihak ibu bapa patut... pihak kerajaan hendaklah... golongan masyarakat seharusnya... instead of just focusing on one point/person and superfluously elaborate it, then your karangan will get more flawless |
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May 21 2013, 08:48 PM
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#10
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654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(maximR @ May 21 2013, 07:07 PM) I'm not letting it get the better of me . There will definitely be a post-mortem on my results , I'll make sure everything , or most of the mistakes will be sorted out . Wow! Looks like you're back and really pumped up,maximR, good for you Thank you ! |
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May 22 2013, 03:14 PM
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#11
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654 posts Joined: Apr 2013 From: Planet Earth |
*Sigh* Finally,can't wait to relish this mid-year semester's holiday after a long and tiring battle,darn,all of the last-minutes revision did wore me out. Gotta make sure I never pull the same trick ever again in this upcoming SPM Trial or else I can just kiss my dreams of getting straight A+ goodbye
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May 25 2013, 10:31 PM
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#12
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654 posts Joined: Apr 2013 From: Planet Earth |
Damn
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May 29 2013, 02:24 AM
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#13
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654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(Boy96 @ May 28 2013, 04:03 PM) I guess you've made a little error there fellas, every student is obliged to complete the Add Math folio whether they like it or not, it's just depends on when do they have to do it, that's all there is to it. |
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May 29 2013, 04:01 PM
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#14
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654 posts Joined: Apr 2013 From: Planet Earth |
QUOTE(Boy96 @ May 29 2013, 02:40 PM) Well, I reckon your teacher keeps it as a secret out of personal reasons or, maybe because you guys haven't even question him/her anything regarding the Add Math folio, so he/she just keeps quiet about it, but sooner or later you will have to do it. Btw, I had no idea that your seniors haven't even got a clue about the Add Math folio. Anyways,FYI, the Add Math folio that we're dealing with in this year kinda resembles with our Kerja Kursus Sejarah Tingkatan 3.This post has been edited by RED-HAIR-SHANKS: May 29 2013, 04:22 PM |
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May 29 2013, 04:20 PM
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#15
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QUOTE(maximR @ May 29 2013, 03:46 PM) There are so many trigonometric identities to remember if you're just starting to play with them , and deriving some of them is a tedious job . |
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May 30 2013, 08:00 AM
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#16
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QUOTE(ZerokillerXX @ May 30 2013, 02:33 AM) recently I found this youtube channel which is quite useful for SPM students. But it only have Maths and Add Maths.. >.< Btw Edunation Malaysia also provide numerous tutoring videos that are quiet helpful too Msia Free Education And they even categorized their Add Maths video chapter by chapter in the facebook page Y=mx+c This post has been edited by RED-HAIR-SHANKS: May 30 2013, 08:11 AM |
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Jun 3 2013, 05:13 PM
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#17
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654 posts Joined: Apr 2013 From: Planet Earth |
This post has been edited by RED-HAIR-SHANKS: Jun 3 2013, 05:25 PM |
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Jun 4 2013, 03:14 PM
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#18
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QUOTE(Krevaki @ Jun 3 2013, 08:14 PM) In the given equation, 1 mol of water is produced and 54.6kJ of heat released. When 27.3kJ of heat is released, how much water is produced? The volume of KOH follows. Oohh, I get it now 1 mol of water = 54.6kJ of heat released so, 0.5 mol of water=27.3kJ of heat released According to the thermochemical equation, 1 mol of KOH reacts with 1 mol of ethanoic acid to form 1 mol of water. So, 0.5 mol of water is formed by the neutralization of 0.5 mol of KOH with 0.5 mol of ethanoic acid. number of mol of KOH=MV 0.5 mol =(2)V V=0.25 x 1000 =250cm3 |
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Jun 4 2013, 03:38 PM
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#19
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Jun 5 2013, 05:35 PM
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#20
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