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Mathematics Maths Logic?, hope you guys can make sense out of it

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TSlin00b
post Jul 10 2009, 11:58 AM, updated 17y ago

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one of my friend pointed this out. admittedly it confuses the heck out of me.

2 * 2 = 2+2;
2 * 3 = 2+2+2;
2 * 4 = 2+2+2+2;
...
x * x = x+x+x+....+x+x (x number of times)

x * x =x^2
therefore,
x^2=x+x+x+x+...+x+x (x number of times)
differentiate,
d/dx(x^2)=2x
d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 (x number of times)
which equals to x

therefore,
2x=x,
2=1
rclxub.gif rclxub.gif rclxub.gif

This post has been edited by lin00b: Jul 10 2009, 01:01 PM
gengenrinni
post Jul 10 2009, 12:06 PM

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rclxub.gif mana question??
exsea
post Jul 10 2009, 12:15 PM

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i think ur logic is flawed
tgrrr
post Jul 10 2009, 12:52 PM

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I'm not really any good in maths and very rusty in calculus already, but why would d(x^2)/dx equals to 2x? Shouldn't it be just x?
TSlin00b
post Jul 10 2009, 12:54 PM

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QUOTE(exsea @ Jul 10 2009, 12:15 PM)
i think ur logic is flawed
*
please point out the flaw


Added on July 10, 2009, 12:55 pm
QUOTE(gengenrinni @ Jul 10 2009, 12:06 PM)
rclxub.gif  mana question??
*
no question (ok, maybe i mis-named the topic). sorry
just a solution?

This post has been edited by lin00b: Jul 10 2009, 12:55 PM
bgeh
post Jul 10 2009, 01:04 PM

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lin00b: My suspicion is that the mismatch occurs because you sum the x's x times, and that x times summing up of x's will incur a second additional x on the other side, done rigourously [because the number of terms to be summed up isn't a constant number anymore, but varies also according to the number x]

edit: confirmed in wikipedia
http://en.wikipedia.org/wiki/Invalid_proof..._that_2_.3D_1_2

This post has been edited by bgeh: Jul 10 2009, 01:05 PM
vivienne85
post Jul 10 2009, 01:43 PM

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numbers never lie to us...


This post has been edited by vivienne85: Jul 10 2009, 01:44 PM
Thinkingfox
post Jul 10 2009, 02:30 PM

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user posted image

Source: Wikipedia: Invalid Proof

This post has been edited by Thinkingfox: Jul 15 2009, 09:00 PM
TSlin00b
post Jul 10 2009, 03:18 PM

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I'm following right up to
2x=(1+1+1+...+1)(x+x+x+...+x)

then its rclxub.gif again
teongpeng
post Jul 13 2009, 01:06 PM

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isnt 2x= x + x ?

vivienne85
post Jul 13 2009, 03:43 PM

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ya...
bgeh
post Jul 14 2009, 12:15 AM

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thinkingfox: No, that isn't my answer, because I can't follow his steps to arrive at that solution

lin00b: I'll give it some thought and see if I can arrive at the same answer through another method, but yes some variation of the product rule will probably be needed here (which seems to be what the wikipedia picture thinkingfox pasted put on his post)
Ichibanichi
post Jul 14 2009, 12:33 AM

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What happen to students now days sweat.gif sweat.gif

Never seem understand the fundamental of function x^2 and 2x.

Plot the graph TS and find the real meaning of differentiate w.r.t (x)

Why /k/ always think it is calculus every time there is d()/dx ???

Don't tell me TS is a uni student
befitozi
post Jul 14 2009, 04:23 AM

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QUOTE(Ichibanichi @ Jul 14 2009, 12:33 AM)
What happen to students now days  sweat.gif  sweat.gif

Never seem understand the fundamental of function x^2 and 2x.

Plot the graph TS and find the real meaning of differentiate w.r.t (x)

Why /k/ always think it is calculus every time there is d()/dx ???

Don't tell me TS is a uni student
*
These math tricks are not uncommon. No harm in looking at it in thinking over it. wink.gif

And what does /k/ has to do with this doh.gif
loongchai
post Jul 14 2009, 06:12 PM

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d/dx(x^2)=2x
d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 (2x number of times)
which equals to 2x

therefore,
2x=2x,
2=2
darkwall
post Jul 14 2009, 11:26 PM

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QUOTE(lin00b @ Jul 10 2009, 11:58 AM)
one of my friend pointed this out. admittedly it confuses the heck out of me.

2 * 2 = 2+2;
2 * 3 = 2+2+2;
2 * 4 = 2+2+2+2;
...
x * x = x+x+x+....+x+x (x number of times)

x * x =x^2
therefore,
x^2=x+x+x+x+...+x+x (x number of times)
differentiate,
d/dx(x^2)=2x
d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 (x number of times)
which equals to x

therefore,
2x=x,
2=1
rclxub.gif  rclxub.gif  rclxub.gif
*
why not like this??

2 * 2 = 2+2;
2 * 3 = 2+2+2;
2 * 4 = 2+2+2+2;
...
x * y = x+x+x+....+x+x (y number of times)
brows.gif brows.gif
SUSahjames
post Jul 15 2009, 01:33 PM

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since when did x become a constant??? <removed>.jpg
TSlin00b
post Jul 15 2009, 06:03 PM

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QUOTE(darkwall @ Jul 14 2009, 11:26 PM)
why not like this??

2 * 2 = 2+2;
2 * 3 = 2+2+2;
2 * 4 = 2+2+2+2;
...
x * y = x+x+x+....+x+x (y number of times)
brows.gif  brows.gif
*
sorry then, lets make it this way:
2 * 2 = 2+2
3 * 3 = 3+3+3
4 * 4 = 4+4+4+4
x * x =x+x+x+...+x (x number of times)


Added on July 15, 2009, 6:08 pm
QUOTE(loongchai @ Jul 14 2009, 06:12 PM)
d/dx(x^2)=2x
d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 (2x number of times)
which equals to 2x

therefore,
2x=2x,
2=2
*
how does d[x+x+x+..+x (x times)]/dx = 1+1+1+...+1 (2x times)?

This post has been edited by lin00b: Jul 15 2009, 06:08 PM
Thinkingfox
post Jul 15 2009, 08:57 PM

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QUOTE(bgeh @ Jul 14 2009, 12:15 AM)
thinkingfox: No, that isn't my answer, because I can't follow his steps to arrive at that solution

lin00b: I'll give it some thought and see if I can arrive at the same answer through another method, but yes some variation of the product rule will probably be needed here (which seems to be what the wikipedia picture thinkingfox pasted put on his post)
*
Oops.. I'm sorry about that.
loongchai
post Jul 15 2009, 11:37 PM

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QUOTE(lin00b @ Jul 15 2009, 06:03 PM)


how does d[x+x+x+..+x (x times)]/dx = 1+1+1+...+1 (2x times)?
*
d/dx(x^2)=2x
d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 (2x number of times)

2x because of d/dx(x^2)=2x

d/dx(x^2) = d/dx(x+x+x+...+x+x)

and

2x = 1+1+1+1+...+1+1+1 (2x number of times)

rclxub.gif



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