Outline ·
[ Standard ] ·
Linear+
Mathematics Maths Logic?, hope you guys can make sense out of it
|
TSlin00b
|
Jul 10 2009, 11:58 AM, updated 17y ago
|
|
one of my friend pointed this out. admittedly it confuses the heck out of me. 2 * 2 = 2+2; 2 * 3 = 2+2+2; 2 * 4 = 2+2+2+2; ... x * x = x+x+x+....+x+x (x number of times) x * x =x^2 therefore, x^2=x+x+x+x+...+x+x (x number of times) differentiate, d/dx(x^2)=2x d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 (x number of times) which equals to x therefore, 2x=x, 2=1 This post has been edited by lin00b: Jul 10 2009, 01:01 PM
|
|
|
|
|
|
exsea
|
Jul 10 2009, 12:15 PM
|
|
i think ur logic is flawed
|
|
|
|
|
|
tgrrr
|
Jul 10 2009, 12:52 PM
|
|
I'm not really any good in maths and very rusty in calculus already, but why would d(x^2)/dx equals to 2x? Shouldn't it be just x?
|
|
|
|
|
|
TSlin00b
|
Jul 10 2009, 12:54 PM
|
|
QUOTE(exsea @ Jul 10 2009, 12:15 PM) i think ur logic is flawed please point out the flaw Added on July 10, 2009, 12:55 pmQUOTE(gengenrinni @ Jul 10 2009, 12:06 PM)  mana question?? no question (ok, maybe i mis-named the topic). sorry just a solution? This post has been edited by lin00b: Jul 10 2009, 12:55 PM
|
|
|
|
|
|
bgeh
|
Jul 10 2009, 01:04 PM
|
|
lin00b: My suspicion is that the mismatch occurs because you sum the x's x times, and that x times summing up of x's will incur a second additional x on the other side, done rigourously [because the number of terms to be summed up isn't a constant number anymore, but varies also according to the number x] edit: confirmed in wikipedia http://en.wikipedia.org/wiki/Invalid_proof..._that_2_.3D_1_2This post has been edited by bgeh: Jul 10 2009, 01:05 PM
|
|
|
|
|
|
vivienne85
|
Jul 10 2009, 01:43 PM
|
|
numbers never lie to us...
This post has been edited by vivienne85: Jul 10 2009, 01:44 PM
|
|
|
|
|
|
Thinkingfox
|
Jul 10 2009, 02:30 PM
|
|
 Source: Wikipedia: Invalid ProofThis post has been edited by Thinkingfox: Jul 15 2009, 09:00 PM
|
|
|
|
|
|
TSlin00b
|
Jul 10 2009, 03:18 PM
|
|
I'm following right up to 2x=(1+1+1+...+1)(x+x+x+...+x) then its  again
|
|
|
|
|
|
teongpeng
|
Jul 13 2009, 01:06 PM
|
|
isnt 2x= x + x ?
|
|
|
|
|
|
vivienne85
|
Jul 13 2009, 03:43 PM
|
|
ya...
|
|
|
|
|
|
bgeh
|
Jul 14 2009, 12:15 AM
|
|
thinkingfox: No, that isn't my answer, because I can't follow his steps to arrive at that solution
lin00b: I'll give it some thought and see if I can arrive at the same answer through another method, but yes some variation of the product rule will probably be needed here (which seems to be what the wikipedia picture thinkingfox pasted put on his post)
|
|
|
|
|
|
Ichibanichi
|
Jul 14 2009, 12:33 AM
|
|
What happen to students now days Never seem understand the fundamental of function x^2 and 2x. Plot the graph TS and find the real meaning of differentiate w.r.t (x) Why /k/ always think it is calculus every time there is d()/dx ??? Don't tell me TS is a uni student
|
|
|
|
|
|
befitozi
|
Jul 14 2009, 04:23 AM
|
|
QUOTE(Ichibanichi @ Jul 14 2009, 12:33 AM) What happen to students now days Never seem understand the fundamental of function x^2 and 2x. Plot the graph TS and find the real meaning of differentiate w.r.t (x) Why /k/ always think it is calculus every time there is d()/dx ??? Don't tell me TS is a uni student These math tricks are not uncommon. No harm in looking at it in thinking over it. And what does /k/ has to do with this
|
|
|
|
|
|
loongchai
|
Jul 14 2009, 06:12 PM
|
Getting Started

|
d/dx(x^2)=2x d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 (2x number of times) which equals to 2x
therefore, 2x=2x, 2=2
|
|
|
|
|
|
darkwall
|
Jul 14 2009, 11:26 PM
|
New Member
|
QUOTE(lin00b @ Jul 10 2009, 11:58 AM) one of my friend pointed this out. admittedly it confuses the heck out of me. 2 * 2 = 2+2; 2 * 3 = 2+2+2; 2 * 4 = 2+2+2+2; ... x * x = x+x+x+....+x+x (x number of times) x * x =x^2 therefore, x^2=x+x+x+x+...+x+x (x number of times) differentiate, d/dx(x^2)=2x d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 (x number of times) which equals to x therefore, 2x=x, 2=1  why not like this?? 2 * 2 = 2+2; 2 * 3 = 2+2+2; 2 * 4 = 2+2+2+2; ... x * y = x+x+x+....+x+x (y number of times)
|
|
|
|
|
|
SUSahjames
|
Jul 15 2009, 01:33 PM
|
|
since when did x become a constant??? <removed>.jpg
|
|
|
|
|
|
TSlin00b
|
Jul 15 2009, 06:03 PM
|
|
QUOTE(darkwall @ Jul 14 2009, 11:26 PM) why not like this?? 2 * 2 = 2+2; 2 * 3 = 2+2+2; 2 * 4 = 2+2+2+2; ... x * y = x+x+x+....+x+x (y number of times)  sorry then, lets make it this way: 2 * 2 = 2+2 3 * 3 = 3+3+3 4 * 4 = 4+4+4+4 x * x =x+x+x+...+x (x number of times) Added on July 15, 2009, 6:08 pmQUOTE(loongchai @ Jul 14 2009, 06:12 PM) d/dx(x^2)=2x d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 ( 2x number of times) which equals to 2xtherefore, 2x= 2x, 2= 2how does d[x+x+x+..+x (x times)]/dx = 1+1+1+...+1 (2x times)? This post has been edited by lin00b: Jul 15 2009, 06:08 PM
|
|
|
|
|
|
Thinkingfox
|
Jul 15 2009, 08:57 PM
|
|
QUOTE(bgeh @ Jul 14 2009, 12:15 AM) thinkingfox: No, that isn't my answer, because I can't follow his steps to arrive at that solution lin00b: I'll give it some thought and see if I can arrive at the same answer through another method, but yes some variation of the product rule will probably be needed here (which seems to be what the wikipedia picture thinkingfox pasted put on his post) Oops.. I'm sorry about that.
|
|
|
|
|
|
loongchai
|
Jul 15 2009, 11:37 PM
|
Getting Started

|
QUOTE(lin00b @ Jul 15 2009, 06:03 PM) how does d[x+x+x+..+x (x times)]/dx = 1+1+1+...+1 (2x times)? d/dx(x^2)=2x d/dx(x+x+x+...+x+x)=1+1+1+1+...+1+1+1 (2x number of times) 2x because of d/dx(x^2)=2xd/dx(x^2) = d/dx(x+x+x+...+x+x) and 2x = 1+1+1+1+...+1+1+1 (2x number of times)
|
|
|
|
|