when is the last day of SPM ?
SPM Thread 08/09 (V 3), SPM is coming soon..!!!! Final days..!!
SPM Thread 08/09 (V 3), SPM is coming soon..!!!! Final days..!!
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Nov 9 2008, 09:06 AM
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#101
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when is the last day of SPM ?
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Nov 9 2008, 02:26 PM
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#102
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Nov 9 2008, 02:29 PM
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#103
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Nov 9 2008, 02:31 PM
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#104
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QUOTE(vick5821 @ Nov 9 2008, 02:29 PM) tis i know lah.sulphate, carbonate, chloride oxide and hydroxide salt which soluble and which insoluble i know..others dunoe no need to know all (unless you are going to attend professional exam). seriously, under spm field, it had been limited. so, just focus to it. |
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Nov 9 2008, 02:35 PM
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#105
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Nov 9 2008, 02:42 PM
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#106
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Nov 9 2008, 02:44 PM
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#107
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apa ni E and G ?
I faham D&G lah .. but .. :hmmm: -- Chow ... shopping This post has been edited by work_tgr: Nov 9 2008, 02:45 PM |
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Nov 9 2008, 05:20 PM
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#108
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Nov 9 2008, 05:22 PM
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#109
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Nov 9 2008, 05:23 PM
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#110
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Nov 9 2008, 05:26 PM
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#111
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Nov 9 2008, 05:28 PM
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#112
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Nov 9 2008, 05:29 PM
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#113
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Nov 9 2008, 05:31 PM
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#114
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Nov 9 2008, 07:33 PM
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#115
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Tak nampak lah. It's gelap at the LHS
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Nov 9 2008, 08:47 PM
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#116
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If x and y are the roots of the equation 2x^2 - 3x + 4 = 0, find the value of:-
i) x^2 + y^2 ii) 1/x + 1/y iii) Hence, construct the quadratic equation with the roots x^2 + 1/y and y^2 + 1/x. i) x^2 + y^2 =(x+y)^2-2xy =(SOR)^2-2(POR) =(3/2)^2-2(2) =-7/4 ii) 1/x + 1/y =(y+x)/xy = SOR/POR =(3/2)/2 =3/4 (x^2 + 1/y)+(y^2 + 1/x) =(yx^2)/y+(xy^2)/x =(yx^3+xy^3)/xy =x^2+y^2 =-7/4 (x^2 + 1/y)(y^2 + 1/x) =[(yx^2)/y][(xy^2)/x] =(xy)^3/xy =(xy)^2 =4 x^2+(7/4)x+4=0 4x^2+7x+16=0 This post has been edited by work_tgr: Nov 9 2008, 08:54 PM |
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Nov 9 2008, 08:54 PM
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#117
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QUOTE(gzavincent @ Nov 9 2008, 08:48 PM) 3rd answer wrong...The answer is x^2+x+6 --opps/ |
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Nov 9 2008, 09:01 PM
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#118
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Nov 9 2008, 09:03 PM
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#119
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Nov 10 2008, 10:43 AM
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#120
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