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 Fixed deposit calculations, More regarding FD

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hivemy
post May 5 2008, 07:54 AM

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QUOTE(arsenal @ May 5 2008, 07:43 AM)
The answer is
5000 x 3.1/100 =155. per year
2 years= 310
*
i think that's not correct. he's calculating by monthly basis.

i forgot my maths formula is secondary school biggrin.gif but what he means should be

Month1 : 5000 x 0.031 + 5000 = 5155
Month2 : 5155 x 0.031 + 5155 = 5314.81
Month3 : 5314.81 x 0.031 + 5314.81 = 5479.56
and so on... anyone knows what kind of formula is this again?

BTW where do you get 3.1% interest per MONTH?? I'm also VERY interested. Most banks gives such interest by YEARLY basis, so you need to divide 12 again oh.. unsure.gif

This post has been edited by hivemy: May 5 2008, 07:55 AM
hivemy
post May 5 2008, 10:13 AM

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QUOTE(*devilelle* @ May 5 2008, 09:41 AM)
the easiest calculation......

5000 X 3.1% x number of days being put into the FD
---------------
      365

for example

= (5000 X 3.1%  / 365 ) X 730 days (2 years)
= RM310 ...

#this what i learned from banking training... dunno still applicable or not....
*
i think that's not applicable for compounding interest.

i found a calculator at http://www.csgnetwork.com/compoundsavingsintcalc.html

not sure if it's accurate tho.. 5000 become 9207.53 after 20 years, i rather invest in stock for 10 years.
hivemy
post May 5 2008, 12:05 PM

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TS want to compound to 20 years (240 months)
Let's assuming 1 year has 365 days
What is the formula to count compounding interest for 7300 days?

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