Coding challenge
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 May 9 2023, 09:23 AM, updated 3y ago
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#1
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Junior Member
148 posts Joined: Jan 2023 
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Try to solve this with any programming language and don't use ChatGPT / google  Let d(n) be defined as the sum of proper divisors of n (numbers less than n which divide evenly into n). If d(a) = b and d(b) = a, where a ≠ b, then a and b are an amicable pair and each of a and b are called amicable numbers. For example, the proper divisors of 220 are 1, 2, 4, 5, 10, 11, 20, 22, 44, 55 and 110; therefore d(220) = 284.The proper divisors of 284 are 1, 2, 4, 71 and 142; so d(284) = 220. Evaluate the sum of all the amicable numbers under 10000. Tullamarine liked this post
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May 9 2023, 01:43 PM
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#2
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Junior Member
148 posts Joined: Jan 2023
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QUOTE(jusbella @ May 9 2023, 09:29 AM) 31626 Share code la. How long you took to complete it?   |
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May 9 2023, 05:16 PM
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#3
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Junior Member
148 posts Joined: Jan 2023
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QUOTE(angch @ May 9 2023, 02:55 PM) CODE angch@mondas code % cat golf.pl for(1..1e4){for($i=$_*2;$i<=1e4;$i+=$_){$a[$i]+=$_}} for(1..1e4){$b=$a[$_];$s+=$_ if$_==$a[$b]&&$_!=$b;} print$s; angch@mondas code % perl golf.pl 31626% Of course I have to golf it. 113 bytes.   |
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