Dec 15 2012, 01:18 AM
QUOTE(Demonic Wrath @ Jun 24 2008, 06:57 PM)
I think he explained until quite simple already.
In this case
Let's say a student get grade B for subject M, grade A for subject N and grade C for subject O.
According to the pointer set by the examination,
So,
Since subject M is worth 6 credits, it'd be 6 credits x 3.00 = 18 grade point
Since subject N is worth 2 credits, it'd be 2 credits x 4.00 = 8 grade point
Since subject O is worth 3 credits, it'd be 3 credits x 2.00 = 6 grade point
So the total is 18 + 8 + 6 = 32 points and to get the GPA you'll need to divide it by 11 credits (6 credits for subject M + 2 credits for subject N + 3 credits for subject O) so in the end you'll get 2.91 GPA for Semester 1.
Sorry , i couldn't understand why subject M,N,O is worth 6,2,3 credits respectively ? Can further explain for me ? Thanks a lot !In this case
Let's say a student get grade B for subject M, grade A for subject N and grade C for subject O.
According to the pointer set by the examination,
CODE
Grade A worth 4.00
Grade B worth 3.00
Grade C worth 2.00
Grade B worth 3.00
Grade C worth 2.00
So,
Since subject M is worth 6 credits, it'd be 6 credits x 3.00 = 18 grade point
Since subject N is worth 2 credits, it'd be 2 credits x 4.00 = 8 grade point
Since subject O is worth 3 credits, it'd be 3 credits x 2.00 = 6 grade point
So the total is 18 + 8 + 6 = 32 points and to get the GPA you'll need to divide it by 11 credits (6 credits for subject M + 2 credits for subject N + 3 credits for subject O) so in the end you'll get 2.91 GPA for Semester 1.
CODE
32/11 = 2.91 GPA
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