Actually u can buy "ibox TP3" cos 9777 only 4 combination....

TP3 only for 1st, 2nd n 3rd price....rm1 pay rm2168..(6500 divide 3)

If ibox tp3, rm2168 divide 4 so payment is rm542....

Meaning, u buy rm1 (9777) ibox tp3, if 1st, 2nd n 3rd price got open, any combination u kena rm542 😋😋

Ibox TP3 should be fine - just double check category under Super 1+3D

Bear in mind ibox TP3 - 1/2/3 prize permutation only for 9777 (does not include special/consolation ya),
if i am not mistaken.

6816 at magnum... no bao

6816 have 12 different way you can wager,
if you bao means to buy all of the combination of 6816 as below

Call it 12 permutation
Minimum RM1 for each number, you will need to wager RM12
If RM2 for each number, you will need to wager RM24
etc

1668
1686
1866
6168

6186
6618
6681
6816

6861
8166
8616
8661

Hope you understand ya, TQ

After scratch those boxes to reveal any number 7 (as prize is based on super 7, so they use the number 7 as their lucky number).
Total them up.... and the prize for each accumulated (number 7) win a prize as below.

Hope its helpful to you

Source

[attachmentid=10027225]

As your number

1 | 2 | 0 dont have any number 7 so no prize, ya
6 | 5 | 4
8 | 9 | 3

7 | 2 | 0    one 7, prize RM5
6 | 5 | 4
8 | 9 | 3

7 | 2 | 0    two 7, prize RM8
6 | 5 | 4
8 | 9 | 7

7 | 2 | 0    three 7, prize RM10
6 | 5 | 4
7 | 9 | 7

7 | 7 | 7    nine 7, prize Mercedes Car
7 | 7 | 7
7 | 7 | 7