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 SPM Students Discussion Thread V3, New Thread: End of an Era!!

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CyberTroop
post Nov 26 2006, 10:50 PM

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So what if got percahan, it's easy. Just need a lil practice.
princess89
post Nov 26 2006, 10:50 PM

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QUOTE(Aztec @ Nov 26 2006, 10:47 PM)
how u know the ques is gonna be like tht?
*
from somewhere... is trustable..
Criptonox89
post Nov 26 2006, 10:50 PM

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QUOTE(MaGNiFiCo @ Nov 26 2006, 10:37 PM)
man u guys has changed the mood and made memorize things to sumtin fun..haha! no doubt dis kind of things (dirty one) will last in our brain longer.. believe it? yeah u bet.. tongue.gif
*
i believe this way is more effective.....don't tell me your brain don't have yellowish thoughts... tongue.gif





ptewee
post Nov 26 2006, 10:54 PM

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QUOTE(evilhomura89 @ Nov 26 2006, 10:42 PM)

As for the anion, or negative ion
Super,(SO4)2-
Flying,(F-)
Nun,(NO3)-
Cheng,(Cl-)
Bra,(Br-)
In,(I-)
Office,(OH)-

The kepekatan of "Cheng Bra In Office" will affect the hasil elektolisis, ion yang lebih pekat dalam elektrolit akan dipilih untuk dinyahcas
*
that totally made me ROFL.... rclxms.gif thumbup.gif
evilhomura89
post Nov 26 2006, 10:56 PM

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From: BM
QUOTE(princess89 @ Nov 26 2006, 10:39 PM)
help me to solve
2x+3y=12
y/x-2x/y=1
i  do until y^2-24-72y+9y^2=12y/2-3y^2/2 here only then stuck
*
y/x-2x/y=1
-> (y^2-2x^2)/xy = 1
2x^2+xy-y^2=0
(2x-y)(x+y)=0

2x+3y=12
2x=12-3y

(12-3y)-y=0
4y=12
y=3

2x-(3)=0
2x=3
x=3/2
Tm89
post Nov 26 2006, 11:00 PM

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By far the easiest for me..

Kumpulan 17
Fiona ( Fl )
Nak ( N )
Cali ( Cl )
Barang ( Br )
I ( Iodin )

SEK Anion
Saya ( SO4)
Nak ( NO3)
Cali ( Cl )
Barang ( Br )
I ( Iodin )
OH ( OH )

SEK Kation
Kalau
Nak
Khawin
Mesti
Ada
Zakat
Fitrah
Supaya
Perkhawinan
Harmoni
Kekal Abadi

Ujian Dalam NaOH dan Ammonia mendakan putih
NZAP => Larut ( NaOH = Zn, Al, Pb )
AMAP => Tak Larut ( Ammonia = Mg, Al, Pb )
* Note that only Ag and Pb changes side...

And for other important part...
Remember how to terangkan penyediaan GARAM and ESTER secara ringkas... 3 marks there
jianee89
post Nov 26 2006, 11:01 PM

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Oh thanks ya...really helps
Axuel
post Nov 26 2006, 11:02 PM

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QUOTE(princess89 @ Nov 26 2006, 10:39 PM)
help me to solve
2x+3y=12
y/x-2x/y=1
i  do until y^2-24-72y+9y^2=12y/2-3y^2/2 here only then stuck
*

Edited.

This post has been edited by Axuel: Nov 26 2006, 11:13 PM
xjuen
post Nov 26 2006, 11:02 PM

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anyone have any idea what to read for physics paper 3 experiment part?
Tm89
post Nov 26 2006, 11:03 PM

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Penyediaan Garam ( Brieflt )
1) MAsukkan asid dalam tabung uji
2) Tambahkan serbuk kuprum oksida sehingga berlebihan
3) Kacaukan
4) PAnaskan shg tepu
5) Sejukkan ke suhu bilik
6) Turaskan
7) bilas ngan sikit air suling
8) keringkan ngan kertas turas

If eksperimen... just add 30cm3 for asid, serbuk wif spatula...and answer with proper sentence
Tm89
post Nov 26 2006, 11:05 PM

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QUOTE(xjuen @ Nov 26 2006, 11:02 PM)
anyone have any idea what to read for physics paper 3 experiment part?
*
Get ready for..
Hukum Gas
Kedalaman Tekanan Cecair
Arus mempengaruhi kekuatan magnet
One of the pita detik eksperimen
Parutan belauan
Inteferens Bunyi

If lucky..maybe one of those will out
Axuel
post Nov 26 2006, 11:06 PM

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QUOTE(xjuen @ Nov 26 2006, 11:02 PM)
anyone have any idea what to read for physics paper 3 experiment part?
*
Erm, maybe interferens gelombang? Cuz my trial exam came out that one and still haven't come out in spm yet. Not sure icon_question.gif
ptewee
post Nov 26 2006, 11:06 PM

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i memorise this the anion SEK:

F**k!!
Some
Noisy
Clowns
Broke
Into
Our
House
despair89
post Nov 26 2006, 11:06 PM

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QUOTE(MaGNiFiCo @ Nov 26 2006, 10:24 PM)
thanks man.. my teacher has gave me sumtin like that b4.. but never memorize it.. tongue.gif

eventho the ayat kind of tunggang terbalik..but nvm lah..
*
Kalau
Nak
Cucuk
Mesti
Ada
Zakar
F*cking
Sluts
Pour
Hot
Cum
Ass

thats how i memorise... really..
Axuel
post Nov 26 2006, 11:07 PM

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QUOTE(Tm89 @ Nov 26 2006, 11:05 PM)
Get ready for..
Hukum Gas
Kedalaman Tekanan Cecair
Arus mempengaruhi kekuatan magnet
One of the pita detik eksperimen
Parutan belauan
Inteferens Bunyi

If lucky..maybe one of those will out
*
Hopefully no cahaya, that bab i hate it dry.gif Hard and boring.
evilhomura89
post Nov 26 2006, 11:07 PM

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From: BM
QUOTE(evilhomura89 @ Nov 26 2006, 10:56 PM)
y/x-2x/y=1
-> (y^2-2x^2)/xy = 1
2x^2+xy-y^2=0
(2x-y)(x+y)=0

2x+3y=12
2x=12-3y

(12-3y)-y=0
4y=12
y=3

2x-(3)=0
2x=3
x=3/2
*
QUOTE(Axuel @ Nov 26 2006, 11:02 PM)
Erm, my answer is x=9/8  , y=13/4

Not sure correct or not.
2x+3y=12
3y=12-2x
y=2(6-x)/3

[y/x-2x/y=1]xy
(xy^2-2x^2y)/xy = 1
xy(y-2x)/xy = 1
y-2x = 1
(12-2x)/3 - 2x = 1
12 - 2x - 6x = 3
12 - 8x = 3
8x = 9
x = 9/8

3y=12-2(9/8)
3y = 39/4
y = 13/4

Not sure is correct or not. smile.gif Pls correct me if got mistakes.
*
U try ganti the nilai x & y into the 2 persamaan and c whether u can get the ans.
Mine, i can get d ans for 2 psm using x=3/2, y=3.
Tm89
post Nov 26 2006, 11:07 PM

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QUOTE(Axuel @ Nov 26 2006, 11:07 PM)
Hopefully no cahaya, that bab i hate it dry.gif Hard and boring.
*
Yea..i oso..but possible in the structure second question of K3...
xjuen
post Nov 26 2006, 11:09 PM

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2x + 3y = 12
y/x - 2x/y = 1

(y²-2x²)/xy = 1
y² - 2x² - xy = 0
2x² - y² + xy = 0
(2x - y)(x + y) = 0
2x = y @ x = -y

2x = 12 - 3y
y = 12 - 3y
4y = 12
y = 3

2x = 3
x = 3/2

erm,hope it's right...
evilhomura89
post Nov 26 2006, 11:12 PM

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From: BM
QUOTE(xjuen @ Nov 26 2006, 11:09 PM)
2x + 3y = 12
y/x - 2x/y = 1

(y²-2x²)/xy = 1
y² - 2x² - xy = 0
2x² - y² + xy = 0
(2x - y)(x + y) = 0
2x = y @ x = -y

2x = 12 - 3y
y = 12 - 3y
4y = 12
y = 3

2x = 3
x = 3/2

erm,hope it's right...
*
The answer is correct.
But, what should we do with this psm - "x+y=0" ??
Abaikan??

This post has been edited by evilhomura89: Nov 26 2006, 11:12 PM
Axuel
post Nov 26 2006, 11:12 PM

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QUOTE(evilhomura89 @ Nov 26 2006, 11:07 PM)
U try ganti the nilai x  & y into the 2 persamaan and c whether u can get the ans.
Mine, i can get d ans for 2 psm using x=3/2, y=3.
*
Ops, sry, my answer is wrong, can't get the correct answer, lolz, thanks for telling. biggrin.gif
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