SPM 2013 Thread
|
|
 Dec 17 2012, 03:27 PM
Return to original view | Post
#1
|
 
Junior Member
506 posts Joined: Feb 2011 
|
Hi guys, I just stumble across an Add-Maths chapter 1 question, and I'm not sure what the question really mean.
Function f(x) = 12/hx+k x =/= -k/h, f(0)= -3, f(7) = 4 Question b) find the value of x, when f(x)=x That's the question I'm have problem with, aren't the image x supposed to be altered somehow compared to the object? x after the function is still x? Thanks. |
|
|
Dec 17 2012, 03:56 PM
Return to original view | Post
#2
|
|
Junior Member
506 posts Joined: Feb 2011
|
QUOTE(reconnaissance @ Dec 17 2012, 03:47 PM) Sure. Thanks! Will try to do it again.That result slip is unimportant at all. No point, except if scholarship is in your mind. There will be a gold-coloured PMR slip which will be issued middle next year. That is the real deal. Added on December 17, 2012, 3:50 pm You have to first define what is the constant h and k, probably your question a. You have to understand the question. You need to find a specific value of x that when you insert in the function results in that value as well.  edit: Do I have to try every number 1 by 1 for the answer? or is there any other way? This post has been edited by IzeStorm: Dec 17 2012, 03:58 PM |
|
|
Dec 17 2012, 07:58 PM
Return to original view | Post
#3
|
|
Junior Member
506 posts Joined: Feb 2011
|
QUOTE(p3nguin @ Dec 17 2012, 04:47 PM) nah you don't. after equating x to the function, just manipulate the equation to get your values of x. Just to clarify, in this case: Thanks!12/(hx+k) = x 12 = x*(hx+k) And then you do whatever's necessary to find x QUOTE(reconnaissance @ Dec 17 2012, 05:12 PM) If you're adding a question, best provide in another post. Noted Some don't go looking at previous post.  |
|
Topic ClosedOptions
|
| Change to: |  0.0602sec
 1.05
 7 queries
 GZIP Disabled
Time is now: 13th December 2025 - 03:14 AM |
Quote