
Why can't I just plug in x+4 in the expression x^2+8x+10 ? Why should I express the function f(x) = y first , and then express y in terms of x ?
This post has been edited by maximR: Jan 15 2012, 07:07 PM
Composite Functions [SPM] Problem
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Jan 15 2012, 07:06 PM, updated 14y ago
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Hello there . I'm currently having a problem with a composite functions question . I know how to solve it , but have no idea as to why I should express y in terms of x before solving it . To get an idea , I've posted the question with a solution :
![]() Why can't I just plug in x+4 in the expression x^2+8x+10 ? Why should I express the function f(x) = y first , and then express y in terms of x ? This post has been edited by maximR: Jan 15 2012, 07:07 PM |
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Jan 16 2012, 06:58 PM
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Hi . Never knew I'll get so many great responses . Anyway , yes , I finally got to the point that I can't understand the concept from all the reference books available , and also the textbooks . Since I'm currently tuition-less , I'll have to resort to asking on the internet , and I've gotten great responses .
From all of the posts above , I figured I'll simplify the main gist of the concept , at least for me : We're finding h(x) , but if we map k(x) to the function x^2+8x+10 , I'll get the value of hk(x) instead and not h(x) . And to find x from k(x) , we'll have to inverse it , by letting y as the subject and then from there , express x in terms of y . Since y is set to be equal to k(x) , which is x+4 , to solve for x , it will be x=y-4 . But then when it comes to here my logic and reasoning doesn't understand this part : SINCE y=x+4 , and x=y-4 , why do we say its h(y) instead and not h(x) ? Is y=y-4 ? |
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Jan 17 2012, 06:32 PM
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QUOTE(CallMeBin @ Jan 15 2012, 11:49 PM) As you can see, Left Equation, the object is y If this is true , that we must express x in terms of y to get the same-object-criteria , then I get it . But shouldn't the right equation be named the image instead ? While, Right equation the object is x No sense right ? So you must make the object equal So since k(x) = y = x+4 So now you have to get x instead of y to fulfill the same-object-criteria Hence, x = y - 4 h(x) = x^2 + 8x + 10 Since, x = y-4 So substitute ! Oh gosh, couldn't believe that I still can explain ! Added on January 17, 2012, 6:33 pm QUOTE(VengenZ @ Jan 16 2012, 09:27 PM) I'm really tired , and after seeing it for a few times I still couldn't get it . I'm really too tired , back from merentas desa . I'll look at it again tomorrow and PM you about it .\p/s : Pretty close . I'm about to get it . Added on January 17, 2012, 6:34 pm QUOTE(doodle @ Jan 17 2012, 01:27 AM) Here are some exercises for your practice. I need guidance for number 9 and 10 .Suppose f(x) = (x-1)^2 - 1. Determine the following. 1. f(0) = ? 2. f(1) = ? 3. f(y) = ? 4. f(x^2) = ? 5. f(1/x) = ? 6. f(f(x)) = ? 7. Given g(x) = 1-x, what is f(g(x))? 8. Given g(x) = 1-x, what is g(f(x))? 9. Given f(g(x)) = x^2 + 4x + 3, and suppose g(x) = ax+b is linear. What are the constants a and b? 10. Given g(f(x)) = -2x^2 + 4x + 1, and suppose g(x) = ax+b is linear. What are the constants a and b? This post has been edited by maximR: Jan 17 2012, 06:37 PM |
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Jan 19 2012, 07:17 PM
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I finally got it after thinking through it many times for several days , with the help of you guys of course . I am proud to say that I got it without the help of a teacher , but a handful of people on the internet .
If we map the value , or expression of k(x) into the function hk(x) , then we're essentially mapping it to make it a much more complex function , but we're looking for h(x) . So , to get h(x) , we inverse k(x) to find x [ if we inverse k(x) , we're finding the initial object - x ] . Hence , after finding it , we can determine h(x) . I tried checking by substitution and finding the inverse in many ways , and found out that it is indeed the case . Then , we're writing it as h(y) because it's just an arbitrarily chosen letter , a place holder since we cannot have a function that is defined as h(x) = y-6 or etc ... So after solving it , we revert it back to h(x) - x-6 . It's exhilarating finally understanding a concept . None of the seniors in my school managed to explain it to me . Now , can we find the inverse of a composition of function , say gf(x) ? This post has been edited by maximR: Jan 19 2012, 07:20 PM |
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