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 Composite Functions [SPM] Problem

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TSmaximR
post Jan 15 2012, 07:06 PM, updated 14y ago

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Hello there . I'm currently having a problem with a composite functions question . I know how to solve it , but have no idea as to why I should express y in terms of x before solving it . To get an idea , I've posted the question with a solution :

user posted image

Why can't I just plug in x+4 in the expression x^2+8x+10 ? Why should I express the function f(x) = y first , and then express y in terms of x ? rclxub.gif

This post has been edited by maximR: Jan 15 2012, 07:07 PM
TSmaximR
post Jan 16 2012, 06:58 PM

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Hi . Never knew I'll get so many great responses . Anyway , yes , I finally got to the point that I can't understand the concept from all the reference books available , and also the textbooks . Since I'm currently tuition-less , I'll have to resort to asking on the internet , and I've gotten great responses . smile.gif

From all of the posts above , I figured I'll simplify the main gist of the concept , at least for me :

We're finding h(x) , but if we map k(x) to the function x^2+8x+10 , I'll get the value of hk(x) instead and not h(x) . And to find x from k(x) , we'll have to inverse it , by letting y as the subject and then from there , express x in terms of y .

Since y is set to be equal to k(x) , which is x+4 , to solve for x , it will be x=y-4 .

But then when it comes to here my logic and reasoning doesn't understand this part : SINCE y=x+4 , and x=y-4 , why do we say its h(y) instead and not h(x) ? Is y=y-4 ?
TSmaximR
post Jan 17 2012, 06:32 PM

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QUOTE(CallMeBin @ Jan 15 2012, 11:49 PM)
As you can see, Left Equation, the object is y
While, Right equation the object is x
No sense right ? So you must make the object equal

So since k(x) = y = x+4
So now you have to get x instead of y to fulfill the same-object-criteria
Hence, x = y - 4

h(x) = x^2 + 8x + 10
Since, x = y-4
So substitute !

Oh gosh, couldn't believe that I still can explain !
*
If this is true , that we must express x in terms of y to get the same-object-criteria , then I get it . But shouldn't the right equation be named the image instead ? hmm.gif


Added on January 17, 2012, 6:33 pm
QUOTE(VengenZ @ Jan 16 2012, 09:27 PM)
Sorry for this shitty drawing tongue.gif (Hope you get the point)

user posted image

h(y) = y^2 - 6 = h(x+4) = (x+4)^2 -6
*
I'm really tired , and after seeing it for a few times I still couldn't get it . I'm really too tired , back from merentas desa . I'll look at it again tomorrow and PM you about it .\

p/s : Pretty close . I'm about to get it . nod.gif


Added on January 17, 2012, 6:34 pm
QUOTE(doodle @ Jan 17 2012, 01:27 AM)
Here are some exercises for your practice.

Suppose f(x) = (x-1)^2 - 1. Determine the following.
1. f(0) = ?
2. f(1) = ?
3. f(y) = ?
4. f(x^2) = ?
5. f(1/x) = ?
6. f(f(x)) = ?
7. Given g(x) = 1-x, what is f(g(x))?
8. Given g(x) = 1-x, what is g(f(x))?
9. Given f(g(x)) = x^2 + 4x + 3, and suppose g(x) = ax+b is linear. What are the constants a and b?
10. Given g(f(x)) = -2x^2 + 4x + 1, and suppose g(x) = ax+b is linear. What are the constants a and b?
*
I need guidance for number 9 and 10 .

This post has been edited by maximR: Jan 17 2012, 06:37 PM
TSmaximR
post Jan 19 2012, 07:17 PM

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I finally got it after thinking through it many times for several days , with the help of you guys of course . I am proud to say that I got it without the help of a teacher , but a handful of people on the internet . smile.gif

If we map the value , or expression of k(x) into the function hk(x) , then we're essentially mapping it to make it a much more complex function , but we're looking for h(x) . So , to get h(x) , we inverse k(x) to find x [ if we inverse k(x) , we're finding the initial object - x ] . Hence , after finding it , we can determine h(x) . I tried checking by substitution and finding the inverse in many ways , and found out that it is indeed the case . Then , we're writing it as h(y) because it's just an arbitrarily chosen letter , a place holder since we cannot have a function that is defined as h(x) = y-6 or etc ... So after solving it , we revert it back to h(x) - x-6 .

It's exhilarating finally understanding a concept . None of the seniors in my school managed to explain it to me .

Now , can we find the inverse of a composition of function , say gf(x) ? smile.gif If yes then I'll get f(x) which will further reinforce my understanding of the concept .

This post has been edited by maximR: Jan 19 2012, 07:20 PM

 

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