Outline ·
[ Standard ] ·
Linear+
Composite Functions [SPM] Problem
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CallMeBin
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Jan 15 2012, 10:05 PM
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I thought you're pro, but you've showed me another example of no one is perfect ! Hahahaha I've problems about this too, I just do the way let, and let .. without knowing the logic . Until before SPM, I asked here in LYN !  I got the logic .. actually you don't have to let, just that it will be very hard to figure out the answer . So for your question, if I don't let , h(x+4) = x^2 + 8x + 10 h(x+4) = (x+4)^2 - 6 h(x)=x^2 - 6 This post has been edited by CallMeBin: Jan 15 2012, 10:10 PM
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CallMeBin
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Jan 15 2012, 11:29 PM
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QUOTE(justarandomboy @ Jan 15 2012, 10:39 PM) Mind explaining how you got the second step from the first? I don't get it.  (x+4)^2 = x^2 + 8x + 16 =)
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CallMeBin
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Jan 15 2012, 11:49 PM
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The first one
h(x+4) = x^2 + 8x + 10
The 2nd one
h(x+4) = x^2 + 8x + 16 - 6
Since they're the same equation which is h(x+4), so they must be the same . (x+4)^2 get x^2 + 8x + 16, so I must minus 6 to get 10
Oh god, if you really can't explain, don't explain, you will make the newbies confused .
Ok let's see h[k(x)] , k(x) is the object So, for convenience, you let y = k(x) Therefore, h(y)
So continue , h(y) = x^2 + 8x + 10
As you can see, Left Equation, the object is y While, Right equation the object is x No sense right ? So you must make the object equal
So since k(x) = y = x+4 So now you have to get x instead of y to fulfill the same-object-criteria Hence, x = y - 4
h(x) = x^2 + 8x + 10 Since, x = y-4 So substitute !
Oh gosh, couldn't believe that I still can explain !
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