Outline ·
[ Standard ] ·
Linear+
WTA vectors
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TS~~SkyShuT_T3r~~
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Apr 25 2011, 07:32 PM, updated 15y ago
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Getting Started

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Find a vector of length 1 which is perpendicular to both u and v. Do not use cross product. u = (-3, 1, 2). v = (4, 0, -8)
How do start with the question? My lecturer haven't discuss cross product with us yet so I think that's why he specified to not use cross product.
So, I tried using dot product to find the equation of plane by letting n = (a, b, c) but I currently have no idea of how to find the variables. Have I missed out something? Or am I using the wrong method?
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bgeh
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Apr 26 2011, 09:13 PM
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QUOTE(~~SkyShuT_T3r~~ @ Apr 25 2011, 11:32 AM) Find a vector of length 1 which is perpendicular to both u and v. Do not use cross product. u = (-3, 1, 2). v = (4, 0, -8) How do start with the question? My lecturer haven't discuss cross product with us yet so I think that's why he specified to not use cross product. So, I tried using dot product to find the equation of plane by letting n = (a, b, c) but I currently have no idea of how to find the variables. Have I missed out something? Or am I using the wrong method? It's solving simultaneous linear equations. You've got the unknown vector x satisfying 2 equations: u.x = 0 v.x = 0 and finally the normalisation condition gives you the final equation: x.x = 1
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