this not single club, this is love club, lulz

hey, nice spec

err.....
One Boy,
One Girl,
2 Hearts beating Wildly!

lulz

it seem like you're in love

hi, but i'm not him, just a person that use this acc

This post has been edited by nickisthemost: Dec 23 2010, 03:49 PM

well, mystery is my name

but you can't take them all into your bed, no ?

NGEKEKEK

yeah, how's things going on bro'tha ?

someone got lost from the south pole, lulz

question :

does polar bear eats penguin ?

oh nice !

how bou't this

You have 20 apples in a basket. 20 children come to you and each one of them ask for an apple. You want to give all the apples to each one of them, but still keep one inside the basket? How will you do it?

Give all the 19 apples to each one of them and give the basket to the last child with the apple still inside it. simple issin't it ? lulz

i believe this is not a question whether it is fair or not

ok another easy one

Larry's father has five sons named Ten, Twenty, Thirty, Forty...Guess what would be the name of the fifth?

This one seems hard, but it's simple! There is a casino and it has 4 gates (let's name them as gate A, B, C and D). Every time you come inside the casino, you have to pay $5 and every time you leave the casino, you again have to pay $5. Also know that, whatever amount of money you carry with you inside the casino, it doubles. For example if you carry $5, it will become $10. You have to go inside the casino through gate A, come out of B, again go inside the casino through gate C and finally come out of gate D. Now, how much money should you carry inside the casino so that when you finally come out of the gate D, you should be left with no (zero amount) money?

so are you

l like bising girl, where you can shut them up by kissing them, lulz

If you keep on guessing the amount of money one after another, then it may take years or may be more than that. There is an easier way! Try solving the problem using algebra.
◦Let's say that the amount which you are carrying inside the casino be 'X'
◦When you enter the casino through gate A, you spend $5, so the amount becomes (X – 5)
◦This amount gets doubled inside the casino and becomes 2 (X – 5), i.e., 2X – 10
◦Now, you make an exit through gate B and again pay $5. So the amount which you have now becomes, (2X – 10 – 5), which is (2X – 15)
◦Again, you enter the casino through gate C and spend $5. This makes the amount (2X – 15) to become (2X – 15 – 5), which is (2X – 20)
◦Once when you are inside, the amount (2X – 20) again gets doubled, i.e. 2 (2X – 20) which is (4X – 40)
◦This time, you will make your final exit through gate D and pay $5. So this makes the amount (4X – 40 – 5), which is (4X – 45).
Now, the condition was that after you have completed the task, you should be left with zero money at the end. So, according to this, the remaining amount of money which you have now, i.e, (4X – 45 ) should be equal to 0.

So, when 4X – 45 = 0; 4X = 45; X = 45 ÷ 4; X = 11.25

Hence, you should carry an amount of $11.25 inside the casino, so that you are left with no money at the end.


how's that ?

i thought he's a smart guy

how much you willing to offer ? lolz

what's your major ?

ic, so what are the things that you want to share with me ?

3 diamond ring ? as he just give away ring not diamond ring lulz

that's hobbes not you lolz

what is fun course O.o ? kama sutra course ? lulz