This one seems hard, but it's simple! There is a casino and it has 4 gates (let's name them as gate A, B, C and D). Every time you come inside the casino, you have to pay $5 and every time you leave the casino, you again have to pay $5. Also know that, whatever amount of money you carry with you inside the casino, it doubles. For example if you carry $5, it will become $10. You have to go inside the casino through gate A, come out of B, again go inside the casino through gate C and finally come out of gate D. Now, how much money should you carry inside the casino so that when you finally come out of the gate D, you should be left with no (zero amount) money?

y???!!

so are you

sales ma
btw, i transfer daddy ownership to skypie...i is too young for daddy duty

starfox!

u the most bising ...muahahahaha

l like bising girl, where you can shut them up by kissing them, lulz

$5?

5?

starbox no choi me. i is sad.

coz u buaya XD

pie pie not as old as u
yer

If you keep on guessing the amount of money one after another, then it may take years or may be more than that. There is an easier way! Try solving the problem using algebra.
◦Let's say that the amount which you are carrying inside the casino be 'X'
◦When you enter the casino through gate A, you spend $5, so the amount becomes (X – 5)
◦This amount gets doubled inside the casino and becomes 2 (X – 5), i.e., 2X – 10
◦Now, you make an exit through gate B and again pay $5. So the amount which you have now becomes, (2X – 10 – 5), which is (2X – 15)
◦Again, you enter the casino through gate C and spend $5. This makes the amount (2X – 15) to become (2X – 15 – 5), which is (2X – 20)
◦Once when you are inside, the amount (2X – 20) again gets doubled, i.e. 2 (2X – 20) which is (4X – 40)
◦This time, you will make your final exit through gate D and pay $5. So this makes the amount (4X – 40 – 5), which is (4X – 45).
Now, the condition was that after you have completed the task, you should be left with zero money at the end. So, according to this, the remaining amount of money which you have now, i.e, (4X – 45 ) should be equal to 0.

So, when 4X – 45 = 0; 4X = 45; X = 45 ÷ 4; X = 11.25

Hence, you should carry an amount of $11.25 inside the casino, so that you are left with no money at the end.


how's that ?

zha dou

Ehh...where got, i choi everyone la ok~~

i'm....looking for buaya actually XD

i dont know algebra, but just nice i'm looking for tuition, u wanna teach me? lol!!

i thought he's a smart guy

daddy buaya u!?

ok saman daddy!!

sure or not..............

i very stupid one

i most stupid

u degree holder, me apa pun tak ada, me stupider~

yor....why i still daddy geh...
and bila i buaya wei ???????

YORRR