let the centre of the circle be O, so join QO and TO, ∠QOT = 72 x 2 = 144, ∠PRS = 180 - 144 = 36

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haih...im a border line student im very poor at those sin tan cos

i only do those quadratic equation,line graph,lines and elevation matrix and transformation

It is 41.12. I got it. You have to cut the base BCD into half. Lets call mid point of BC as T. So it will form a triangle ATD. AD is 8cm and TD is root of 84cm. Then, tan ATD = 8/(root of 84). Hence solve.

(10^2 - 4^2) = 84cm

Both ABD and ACD are right-angled triangles as A is vertically above D and BD=CD=10cm. This shows that base BDC is an isosceles triangle. Thus you need to cut BDC into half to form a right-angled triangle so that you can obtain length of TD. Using TD as adjacent side and AD as the opposite side, you'll be able to calculate angle ATD.

I apologize if this sounds complicated and confusing, I advise you to sketch the triangles for better understanding.

1 more question
how should we write the inequalities if

The number of Y must exceed the number of X by at most 100

hey.what did u guys put for the drover's wife 1st question??i forgot the question..i can only recall i put that she is on guard against the snake something like that..is it correct??

need help

cannot use mah...you use ka?