and one of the 2664 passwords is LAME

hard to explain so I decided not to, lol

Hope you can understand what I'm saying...

For easy understanding, draw the vector out:
draw OP, then draw OQ start from P. Then you have two lines, OP and PQ. Draw a line from O to Q, that's the vector. You should have a Triangle now if you get what I'm saying. Both line OP and PQ are 2 units.
Angle OPQ is 120 degree. Use any way you like to get the lenght for OQ.

Hope you can understand my drawing again

you cant do from the original diagram, you have to draw another diagram

---

Added on November 26, 2010, 11:16 pmmeans the magnitude of the vector, for easy understanding, equals to the length

This post has been edited by bryanyeo: Nov 26 2010, 11:16 PM

yup, in short, the length of the resultant vector

magnitude not the same. but vector 1 equals to a constant times vector 2.

So if I let k = constant, vector 1 = P , vector 2 = Q,
P = kQ

you joined LYN since Primary School? lol

Actually you can. Because the whole function is y only, is the same if you replace all y with alpha or beta or x or whatever you like. If you change it back, you can't solve it because you get h(x-2) and what you need is h(x)

i got

-1<x≤-1/2
3≤x<5

1/2 pi is 90 degree.
PQ=QR, so angle QPR = 45 degree which is 1/4 pi.
area of sector is 1/2 x 8^2 x 1/4 x 3.142

---

Added on November 27, 2010, 12:14 pmmy solution:

2x^2 - 4x - 3 ≥ x
2x^2 - 5x -3 ≥ 0
(2x+1)(x-3)≥0
draw the inequality graph
x≤-1/2 , x≥3

x>-1 , x<5

therefore,
-1<x≤-1/2
3≤x<5

This post has been edited by bryanyeo: Nov 27 2010, 12:14 PM

1/2 pi is 90 degree, so actually it's a right angle triangle. Just use 1/2 x base x height, which is 1/2 x 8 x 8

Actually got one question has a minor problem. Drawing graph one. It states that the range for y is -27<y<9, but 9 is not the turning point, in fact the graph will slightly exceed 9