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 If you do double window tinting, how is, Infra-Red Heat Rejection percent?

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TSunknown warrior
post Nov 3 2009, 05:49 PM, updated 17y ago

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Let say first layer is 65% Heat rejection and you install another layer which gives 82% Heat rejection, what's the total
heat rejection?

65+82=147%?

or

65<82% = 82% + 5% = 86.1%?

or


just 82%

Any Window Tinting expert here?
TSunknown warrior
post Nov 3 2009, 06:05 PM

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QUOTE(imperialrealcs @ Nov 3 2009, 06:01 PM)
1st tint 65% so left 35% not rejected..
so out of 35% not rejected, 82% will be rejected by second tint.
so after all that the not rejected rate should be around 7%
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Sounds logical but is it like that?
TSunknown warrior
post Nov 3 2009, 06:44 PM

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QUOTE(deeplyheartbroken @ Nov 3 2009, 06:28 PM)
I checked with the tinting shop before, they cannot apply another tint on the existing thin because it won't last & hold.
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I've been told depends on the first layer of tinting, if done properly, it will hold if apply the 2nd.
TSunknown warrior
post Nov 4 2009, 09:12 AM

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QUOTE(khuirene @ Nov 3 2009, 09:20 PM)
abg JPJ will smile if double tint... smile.gif)
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Not really, even my first tint doesn't look tinted, it's clear as day. The sales guy did scratch his head when I told him I didn't want it to look like tinted, that's why I'm opting for 2nd clear layer as well but with higher heat rejection percentage. Dunno if the rate is going to add up.

Some of the shops told me it's added up, some told me it adds up 5% extra, some told me, it's the higher percentage that counts.

I am confuse.
TSunknown warrior
post Nov 6 2009, 08:32 AM

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QUOTE(tester1979 @ Nov 5 2009, 10:29 PM)
here's how to calculate, mathematically that is:-

you tint 65% heat rejection first and then on top of it another 82% tint. this means that sunlight passes through the 82% tint then only 65% tint.
light = 100% = 1
tint 1 = 82% = 0.82
tint 2 = 65% = 0.65

total heat after passing through 82% tint = 1 - 1x(0.82)
                                                           = 0.18

total heat after passing through 65% tint = 0.18 - 0.18x(0.65)
                                                            = 0.063

so in percentage, total heat that will go through both tints = 6.3%

if you tint 82% first and then on 65%, you'll get the same results.

but here's the catch, heat rejection rating is not equal to the visible light rating.....

you need to know what is the visible light rating/percentage for the tints because this is what JPJ uses to determine if you break the law.  the law says visible light penetration through windscreen needs to be at least 75% if I recall correctly.  if you know what is the visible light rating, you can use the same formula above to calculate the total visible light penetration.

but the problem is, car windscreen has its own filter value that sometimes causes not 100% visible light to go through even without tinting.

you will need to take this into account.

the best way to measure is to use the tool JPJ uses to measure the visible light penetration for your windsreen.

eg. if your tinting has 90% light penetration for 1st tint and another 90% light penetration for 2nd tint, and another 95% penetration for your own original windscreen, the total light penetration would be 76.95%.

hope this helps..........
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Why should filtering starts at 82% since infra red wave will hit 65% layer first?

This is the order:

IR Heat---> Window---->65% Tint----->82% Tint.

Edit: Anyway, thanks for the input. Appreciate it.

This post has been edited by unknown warrior: Nov 6 2009, 08:39 AM

 

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