This post has been edited by sphiroth: Nov 3 2009, 06:57 PM
If you do double window tinting, how is, Infra-Red Heat Rejection percent?
If you do double window tinting, how is, Infra-Red Heat Rejection percent?
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Nov 3 2009, 06:55 PM
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imperialrc explanation is logical but let say the filtration is like filtering a sand with 1mm size filter, anything larger will not go through. Take the filtered sand (which is less than 1mm) and filter it again with the same filter will definitely pointless right? Same with light which is filtered by its wavelength.
This post has been edited by sphiroth: Nov 3 2009, 06:57 PM |
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Nov 3 2009, 08:59 PM
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QUOTE(imperialrealcs @ Nov 3 2009, 07:36 PM) but ur example got some flaw.. Its quite the same process actually. The heat is actually IR light ang light are categorized depending on its wavelength (and also frequency). By filtering certain wavelength, in this case IR, we are able to reduce heat going through the tint.sand is a thing with weight and shape etc while light/heat is a form of energy.. tint film limit/reject, not filter the heat.. im not sure but what i mean is if u flow 1 litre of water from a pipe, the x(can be anything) item will limit how much the water can go through the pipe while if "filter" means what substance in the water can go through and which cant such as condiments or minerals contained in water juz my though This post has been edited by sphiroth: Nov 3 2009, 09:00 PM |
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