as i mentioned before, for each row, i neglect the midle block. let me try again to explain more detail
consider the first row:


let see the second row now:


now the last row:

finally, i found the answer. i think this is the accurate one. almost same as my previous sequence. by using this methode, the middle column will not be neglected anymore.
let me try again to explain this.

first: move last column 1 step down
second: move all the columns to right (1 step)
third: change shape. (invert from my previous third step). therefore o → ▲; ▲ → x; x → o;

use this sequence for 1st block to 2nd block to 3rd block. 3rd block to 4th block, just rotate it 90 degrees clockwise (as mentioned before). then repeat it for the other row.

sorry, last time i cant see the sequence for the middle column. therefore i try to 'divide by 2' my previous sequence.