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kenloh7
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Sep 14 2009, 12:18 AM
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I've got a projectiles question here
A ball is thrown upward from the top of a building with an initial velocity of 70m/s at an angle of 35 degrees above the horizontal. Given that the height of the building is 65m. Calculate the time for the ball to reach the ground.
My answer is 1.385s.
I hope that i do it right otherwise i will have my scholarship withdrawn and needed to pay an extra RM840.
Thanks for the help
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kenloh7
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Sep 14 2009, 06:08 PM
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QUOTE(Eventless @ Sep 14 2009, 03:22 PM) It would be easier if you show the steps that you've used to come up with that number and what is the value for g that you have used in your calculation. You would need to find out how high the ball will get based on the launch parameters. It's not going straight up so you will need to use trigonometry to get the vertical component of the velocity. This information will provide the time it takes for the ball to go up and stop and the additional vertical distance traveled upward from the top of the building. With the new height and the height of the building, figure out how long it takes for the ball to fall to the ground. Add the time for the ball to go up and stop and the time to fall from its new height to get the total travel time. actual answer is 9.57s,i did not understand the question fully ,that is y i got 1.385s
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kenloh7
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Sep 15 2009, 12:03 PM
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ive fully understood wat u guys r saying,i misinterpret the question wrong thats y i got -9.57 instead of a positive value,i put it as throwing 35degrees down instead of throwing it up
question solved and completed.
This post has been edited by kenloh7: Sep 15 2009, 12:06 PM
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